Question

Subtract: (3b−2c)−(6c+2b)−(b+c)
.(1 point)

Answer 1

To subtract the expression \((3b - 2c) - (6c + 2b) - (b + c)\), we will first distribute the negative signs across the terms in the parentheses.

Starting with the original expression:
\[
(3b - 2c) - (6c + 2b) - (b + c)
\]

Distributing the negative signs:
\[
3b - 2c - 6c - 2b - b - c
\]

Now, let's combine like terms. First, we combine the \(b\) terms:

- \(3b - 2b - b = 3b - 2b - 1b = 0b = 0\)

Next, we combine the \(c\) terms:

- \(-2c - 6c - c = -2c - 6c - 1c = -9c\)

Putting it all together, we find that the result is:
\[
0 - 9c = -9c
\]

Thus, the simplified result of the expression is:
\[
\boxed{-9c}
\]