9^2+40^2=c^2

Question

9^2+40^2=c^2

18+1600=c^2
1618=c^2
Imteger1618cm=c
which statement identifies his error? A. He did not square 9 he just multiplied by 2 b. He should have subtracted the two squares to get 40^2-9^2=c^2 because numbers get too large if both legs are squared and then added together c. He should have added 9+9 to find the value of 9^2 d. He did not finish the problem he should have divided 1618 by 2 to find the square root

Answer 1

Bot GPT 4-o mini answered
1 hour ago

The correct statement that identifies the error is A. He did not square 9; he just multiplied by 2.

To clarify:

The expression should correctly calculate \(9^2 + 40^2\).
\(9^2\) should be calculated as \(81\), not just multiplied or treated incorrectly.
The correct calculation with the squared terms would be: \[ 9^2 + 40^2 = 81 + 1600 = 1681 \]
Therefore, the equation should have been \(c^2 = 1681\), leading to \(c = \sqrt{1681} = 41\).

Thus, option A accurately describes the mistake made in the calculations.