Let's solve both problems step by step.
Question 1: Add \( 2 \frac{1}{5} + 3 \frac{2}{3} \)
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Convert the mixed numbers to improper fractions:
\[ 2 \frac{1}{5} = \frac{2 \times 5 + 1}{5} = \frac{10 + 1}{5} = \frac{11}{5} \] \[ 3 \frac{2}{3} = \frac{3 \times 3 + 2}{3} = \frac{9 + 2}{3} = \frac{11}{3} \]
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Find a common denominator. The least common denominator (LCD) for 5 and 3 is 15.
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Convert both fractions to have the common denominator:
\[ \frac{11}{5} = \frac{11 \times 3}{5 \times 3} = \frac{33}{15} \] \[ \frac{11}{3} = \frac{11 \times 5}{3 \times 5} = \frac{55}{15} \]
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Add the two fractions:
\[ \frac{33}{15} + \frac{55}{15} = \frac{33 + 55}{15} = \frac{88}{15} \]
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Convert the improper fraction back to a mixed number:
\[ \frac{88}{15} = 5 \frac{13}{15} \]
So the answer to Question 1 is 5 13/15 (or "513 over 15").
Question 2: Subtract \( 8 \frac{5}{10} - 4 \frac{2}{5} \)
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Convert the mixed numbers to improper fractions:
\[ 8 \frac{5}{10} = \frac{8 \times 10 + 5}{10} = \frac{80 + 5}{10} = \frac{85}{10} \] \[ 4 \frac{2}{5} = \frac{4 \times 5 + 2}{5} = \frac{20 + 2}{5} = \frac{22}{5} \]
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Find a common denominator. The least common denominator (LCD) for 10 and 5 is 10.
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Convert the second fraction:
\[ \frac{22}{5} = \frac{22 \times 2}{5 \times 2} = \frac{44}{10} \]
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Subtract the two fractions:
\[ \frac{85}{10} - \frac{44}{10} = \frac{85 - 44}{10} = \frac{41}{10} \]
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Convert to a mixed number:
\[ \frac{41}{10} = 4 \frac{1}{10} \]
So the answer to Question 2 is 4 1/10 (or "41 tenth").
Final Answers:
- Question 1: 5 13/15
- Question 2: 4 1/10