1-Variable Quadratic Inequalities Quick Check

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Question
What is the solution set to the quadratic inequality x2−4x−21>0
?(1 point)
Responses

−3≤x≤7
negative 3 is less than or equal to x comma x is less than or equal to 7

x<−3 or x>7
x is less than negative 3 o r x comma negative 3 o r x is greater than 7

x≤−3 or x≥7
x is less than or equal to negative 3 o r x comma negative 3 o r x is greater than or equal to 7

−3<x<7

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
1 hour ago

To solve the quadratic inequality \(x^2 - 4x - 21 > 0\), we first need to find the roots of the corresponding equation \(x^2 - 4x - 21 = 0\).

We can factor the quadratic:

\[ x^2 - 4x - 21 = (x - 7)(x + 3) = 0 \]

The roots are \(x = 7\) and \(x = -3\).

Next, we will test intervals to determine where the quadratic expression is greater than zero. The critical points divide the number line into three intervals:

  1. \( (-\infty, -3) \)
  2. \( (-3, 7) \)
  3. \( (7, \infty) \)

We'll test each interval:

  1. Interval \( (-\infty, -3) \): Choose \(x = -4\): \[ (-4 - 7)(-4 + 3) = (-11)(-1) = 11 > 0 \] The expression is positive.

  2. Interval \( (-3, 7) \): Choose \(x = 0\): \[ (0 - 7)(0 + 3) = (-7)(3) = -21 < 0 \] The expression is negative.

  3. Interval \( (7, \infty) \): Choose \(x = 8\): \[ (8 - 7)(8 + 3) = (1)(11) = 11 > 0 \] The expression is positive.

Now, we can summarize the results:

  • The expression is positive in the intervals \( (-\infty, -3) \) and \( (7, \infty) \).

Thus, the solution set to the quadratic inequality \(x^2 - 4x - 21 > 0\) is:

\[ \boxed{x < -3 \text{ or } x > 7} \]

Therefore, the correct response is:

x < -3 or x > 7.