Proving Similar Triangles Practice

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Question
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Triangle upper Y upper X upper Z is divided into triangle upper Y upper B upper A and quadrilateral upper A upper B upper Z upper X by horizontal line upper A upper B.

If △AYB∼△XYZ
, and AB=5
, AY=12
, AY=AX
, and BY=BZ
, then what is the length of BZ
? Enter your response as a mixed fraction if needed.

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To find the length of \( BZ \), we can use the property of similar triangles.

Since \( \triangle AYB \sim \triangle XYZ \), we can set up a proportion based on the corresponding sides. The given information is as follows:

  • \( AB = 5 \)
  • \( AY = 12 \)
  • \( AX = AY = 12 \) (from the problem statement)
  • \( BY = BZ \)

Let's denote the lengths:

  • The side lengths of \( \triangle AYB \):

    • \( AY = 12 \)
    • \( AB = 5 \)
  • The side lengths of \( \triangle XYZ \):

    • Corresponding side \( AX = 12 \)
    • Let \( BZ = x \) (which is equal to \( BY \))

Now, we can set up a proportion based on the lengths of the similar triangles:

\[ \frac{AY}{AX} = \frac{AB}{XZ} = \frac{BY}{BZ} \]

Substituting the known values into this proportion:

\[ \frac{12}{12} = \frac{5}{XZ} = \frac{BY}{x} \]

Since \( \frac{12}{12} = 1 \), we also have:

\[ \frac{5}{XZ} = 1 \quad \text{and therefore} \quad XZ = 5 \]

Now, since \( BY = BZ = x \) and substituting back into our proportion:

\[ \frac{BY}{BZ} = 1 \implies BY = BZ \]

Now we can use what we have from \( BY \):

\[ \frac{12}{12} = 1 \quad \text{therefore, } BY \text{ and } BZ \text{ are equal.} \]

From the properties of similar triangles, we know that:

\[ \frac{AB}{AY} = \frac{BY}{BZ} = \frac{5}{12} \]

Utilizing the property \( BY = BZ \), we can say:

If \( AB = 5 \) and \( BY = x \), we can relate this through the ratios from the triangles. Setting this equal gives us:

\[ x = BY = \frac{5}{1} \cdot \frac{1}{12} = \frac{5}{12} \]

And we already defined \( BY = BZ \):

Thus,

\[ BZ = x = \frac{5}{12} \]

In conclusion, the length of \( BZ \) is:

\[ \boxed{\frac{5}{12}} \]