Asked by SS
One leg of a right triangle is 5 centimeters longer than the other leg. What quadratic inequality represents the length of the shorter leg, x, when the hypotenuse is at least 13 centimeters long?(1 point)
Responses
x2+(5x)2≤132
x squared plus 5 x squared is less than or equal to 13 squared
x2+(x+5)2≤132
x squared plus open paren x plus 5 close paren squared is less than or equal to 13 squared
x2+(5x)2≥132
x squared plus 5 x squared is greater than or equal to 13 squared
x2+(x+5)2≥132
Responses
x2+(5x)2≤132
x squared plus 5 x squared is less than or equal to 13 squared
x2+(x+5)2≤132
x squared plus open paren x plus 5 close paren squared is less than or equal to 13 squared
x2+(5x)2≥132
x squared plus 5 x squared is greater than or equal to 13 squared
x2+(x+5)2≥132
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve this problem, we first define the legs of the right triangle. Let \( x \) be the length of the shorter leg. Since one leg is 5 centimeters longer than the other, the other leg can be described as \( x + 5 \).
According to the Pythagorean theorem, the relationship between the legs and the hypotenuse \( c \) of a right triangle is given by:
\[
x^2 + (x + 5)^2 = c^2
\]
In this case, we want the hypotenuse to be at least 13 centimeters long, which means:
\[
c \geq 13
\]
Thus, we need to ensure that:
\[
x^2 + (x + 5)^2 \geq 13^2
\]
Calculating \( 13^2 \):
\[
13^2 = 169
\]
Substituting this into our inequality gives us:
\[
x^2 + (x + 5)^2 \geq 169
\]
Now we simplify \( (x + 5)^2 \):
\[
(x + 5)^2 = x^2 + 10x + 25
\]
Therefore, our inequality becomes:
\[
x^2 + x^2 + 10x + 25 \geq 169
\]
Combining like terms results in:
\[
2x^2 + 10x + 25 \geq 169
\]
Subtracting 169 from both sides gives:
\[
2x^2 + 10x - 144 \geq 0
\]
To match this with the original responses, we will analyze the provided options. The correct quadratic inequality representing the length of the shorter leg \( x \) is:
\[
x^2 + (x + 5)^2 \geq 13^2
\]
Thus, the correct response is:
**\( x^2 + (x + 5)^2 \geq 13^2 \)**.
According to the Pythagorean theorem, the relationship between the legs and the hypotenuse \( c \) of a right triangle is given by:
\[
x^2 + (x + 5)^2 = c^2
\]
In this case, we want the hypotenuse to be at least 13 centimeters long, which means:
\[
c \geq 13
\]
Thus, we need to ensure that:
\[
x^2 + (x + 5)^2 \geq 13^2
\]
Calculating \( 13^2 \):
\[
13^2 = 169
\]
Substituting this into our inequality gives us:
\[
x^2 + (x + 5)^2 \geq 169
\]
Now we simplify \( (x + 5)^2 \):
\[
(x + 5)^2 = x^2 + 10x + 25
\]
Therefore, our inequality becomes:
\[
x^2 + x^2 + 10x + 25 \geq 169
\]
Combining like terms results in:
\[
2x^2 + 10x + 25 \geq 169
\]
Subtracting 169 from both sides gives:
\[
2x^2 + 10x - 144 \geq 0
\]
To match this with the original responses, we will analyze the provided options. The correct quadratic inequality representing the length of the shorter leg \( x \) is:
\[
x^2 + (x + 5)^2 \geq 13^2
\]
Thus, the correct response is:
**\( x^2 + (x + 5)^2 \geq 13^2 \)**.
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