Find the range of the function for the given domain.

f(x)=3x+7;{−2,−1,0,1,2}
𝑓
(
𝑥
)
=
3
𝑥
+
7
;
{

2
,

1
,
0
,
1
,
2
}

Choose the correct answer below.

(1 point)
Responses

{1,4,7,10,13}
{
1
,
4
,
7
,
10
,
13
}
start set 1 comma 4 comma 7 comma 10 comma 13 end set

{0,4,7,10,14}
{
0
,
4
,
7
,
10
,
14
}
start set 0 comma 4 comma 7 comma 10 comma 14 end set

{1,5,7,11,13}
{
1
,
5
,
7
,
11
,
13
}
start set 1 comma 5 comma 7 comma 11 comma 13 end set

{1,5,6,11,13}

1 answer

To find the range of the function \( f(x) = 3x + 7 \) for the given domain \({-2, -1, 0, 1, 2}\), we will evaluate the function at each of the domain values.

  1. For \( x = -2 \): \[ f(-2) = 3(-2) + 7 = -6 + 7 = 1 \]

  2. For \( x = -1 \): \[ f(-1) = 3(-1) + 7 = -3 + 7 = 4 \]

  3. For \( x = 0 \): \[ f(0) = 3(0) + 7 = 0 + 7 = 7 \]

  4. For \( x = 1 \): \[ f(1) = 3(1) + 7 = 3 + 7 = 10 \]

  5. For \( x = 2 \): \[ f(2) = 3(2) + 7 = 6 + 7 = 13 \]

Now, we compile the outputs: \[ f(-2) = 1, \quad f(-1) = 4, \quad f(0) = 7, \quad f(1) = 10, \quad f(2) = 13 \]

The range of the function for the given domain is: \[ {1, 4, 7, 10, 13} \]

So the correct answer is: \[ {1, 4, 7, 10, 13} \]

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