To multiply the polynomials \((2k + 3)(3k + 2)\), we'll use the distributive property (also known as the FOIL method for binomials):
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Multiply the first terms: \[ 2k \cdot 3k = 6k^2 \]
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Multiply the outer terms: \[ 2k \cdot 2 = 4k \]
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Multiply the inner terms: \[ 3 \cdot 3k = 9k \]
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Multiply the last terms: \[ 3 \cdot 2 = 6 \]
Now, combine all these results: \[ 6k^2 + 4k + 9k + 6 \]
Combine the like terms (\(4k\) and \(9k\)): \[ 6k^2 + 13k + 6 \]
Thus, the final answer in standard form is: \[ \boxed{6k^2 + 13k + 6} \]