Use the image to answer the question.

Triangle upper X upper Y upper Z and a dotted line are graphed on a coordinate plane. The x- and y-axes range from negative 7 to 7 in increments of 1. The dotted line is labeled axis of reflection and follows y equals 1.

Find the coordinates of Z′
after a reflection across y=1
.

(1 point)
Responses

Z′(−4,0)
upper Z prime left parenthesis negative 4 comma 0 right parenthesis

Z′(6,2)
upper Z prime left parenthesis 6 comma 2 right parenthesis

Z′(4,0)
upper Z prime left parenthesis 4 comma 0 right parenthesis

Z′(−4,2)
upper Z prime left parenthesis negative 4 comma 2 right parenthesis

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To find the coordinates of \( Z' \) after a reflection across the line \( y = 1 \), we first need to identify the original coordinates of point \( Z \) and then apply the reflection transformation.

Let’s say the original coordinates of point \( Z \) are \( (x, y) \).

The formula for reflecting a point \( (x, y) \) across the line \( y = k \) is given by:

  • The x-coordinate remains the same: \( x' = x \)
  • The new y-coordinate is: \( y' = 2k - y \)

In our case, \( k = 1 \). Therefore, the new y-coordinate after reflection across \( y = 1 \) would be: \[ y' = 2(1) - y = 2 - y \]

Assuming \( Z \) has coordinates \( (x, y) \).

To find the coordinates of \( Z' \), we can plug in the y-coordinate of point \( Z \) into the formula \( y' = 2 - y \).

Considering the options provided:

  1. \( Z'(-4, 0) \)
  2. \( Z'(6, 2) \)
  3. \( Z'(4, 0) \)
  4. \( Z'(-4, 2) \)

To find the reflection across line \( y=1 \) for an example \( Z(4,0) \):

  • Original point: \( (4, 0) \)
  • New coordinate would be:
    • x-coordinate remains the same: \( x' = 4 \)
    • y-coordinate: \( y' = 2 - 0 = 2 \)

Thus, the reflected point \( Z' = (4, 2) \).

Among the options provided, the correct reflection, assuming the original point was \( (4, 0) \), would be: \[ Z' = (4, 2) \]

Therefore, the answer is:

Z′(6,2).