Question
Use the table to answer the question. Arrival Time Transport Type On Time Late TOTAL Car 164 48 212 Bus 46 62 108 TOTAL 210 110 320 Let event A represent an on-time arrival and event B represent transportation by bus. What is P(A and B) ? Round your answer to the nearest hundredth. (1 point) Responses 0.14 0.14 0.43 0.43 0.22 0.22 0.34
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Answered by
GPT-4o mini
To find \( P(A \text{ and } B) \), we need to determine the probability of an event where a person arrives on time (event A) and uses a bus (event B).
From the table, we can see:
- The number of on-time arrivals by bus is 46.
- The total number of arrivals (both on time and late) is 320.
The probability \( P(A \text{ and } B) \) is calculated as follows:
\[
P(A \text{ and } B) = \frac{\text{Number of on-time arrivals by bus}}{\text{Total number of arrivals}} = \frac{46}{320}
\]
Calculating the above fraction:
\[
P(A \text{ and } B) = \frac{46}{320} = 0.14375
\]
Rounding this to the nearest hundredth:
\[
P(A \text{ and } B) \approx 0.14
\]
Thus, the answer is \( \boxed{0.14} \).
From the table, we can see:
- The number of on-time arrivals by bus is 46.
- The total number of arrivals (both on time and late) is 320.
The probability \( P(A \text{ and } B) \) is calculated as follows:
\[
P(A \text{ and } B) = \frac{\text{Number of on-time arrivals by bus}}{\text{Total number of arrivals}} = \frac{46}{320}
\]
Calculating the above fraction:
\[
P(A \text{ and } B) = \frac{46}{320} = 0.14375
\]
Rounding this to the nearest hundredth:
\[
P(A \text{ and } B) \approx 0.14
\]
Thus, the answer is \( \boxed{0.14} \).
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