The function given is \( f(x) = x^2 \). To find the missing value in the x-values and the corresponding y-values for this function, we can calculate \( f(x) \) for the x-values provided.
We know:
- When \( x = -2 \): \( f(-2) = (-2)^2 = 4 \)
- When \( x = -1 \): \( f(-1) = (-1)^2 = 1 \)
- When \( x = 0 \): \( f(0) = 0^2 = 0 \)
- When \( x = 1 \): \( f(1) = 1^2 = 1 \)
The ordered pairs for these calculations are:
- For \( x = -2 \), \( y = 4 \) → ordered pair: \((-2, 4)\)
- For \( x = -1 \), \( y = 1 \) → ordered pair: \((-1, 1)\)
- For \( x = 0 \), \( y = 0 \) → ordered pair: \((0, 0)\)
- For \( x = 1 \), \( y = 1 \) → ordered pair: \((1, 1)\)
From the values of \( y \) listed in your question (0, 1, 4) and the pattern established, we need to find the corresponding \( x \) value when \( f(x) = 4\).
The only missing value of \( x \) that will produce \( f(x) = 4 \) is:
- When \( x = 2 \): \( f(2) = 2^2 = 4 \)
Thus, the missing value for \( x \) in the list is \( 2 \).
So, the completed lists will be: X: -2, -1, 0, 1, 2 Y: 4, 1, 0, 1, 4
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