Question

A compressed gas cylinder contains 1.00 103 g of argon gas. The pressure inside the cylinder is 2035 psi (pounds per square inch) at a temperature of 15°C. How much gas remains in the cylinder if the pressure is decreased to 610. psi at a temperature of 30.°C?

Thanks for the help in advance :)

Answers

DrBob222
Do you mean that you open the valve on the cylinder and release Ar gas until the pressure is decreased to 610 psi at 30 C?
kristen
ohh yes i think so
DrBob222
I would go to google, type in "2035 psi to atmospheres" without the quotation marks. Do the same for 610 psi. Then use PV = nRT to calculate n remaining in the vessel and convert that to grams. Subtract from the initial amount to obtain the grams Ar remaining.
kristen
i found both atmospheres
2035=138.473537
610=41.508038

so it would be 1.00103(2035)=?
DrBob222
I don't think so. You haven't used PV = nRT
I would substitute P, V, R, and T (don't forget to change T t Kelvin) from the final conditions and calculate n, number of moles. Then moles = grams/molar mass and determine grams, then subtract from the initial grams to find that remaining.

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