To balance the chemical equation for the reaction between aluminum (Al) and hydrochloric acid (HCl) to produce aluminum chloride (AlCl₃) and hydrogen gas (H₂), we follow these steps:
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Write the unbalanced equation: \[ \text{Al} + \text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2 \]
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Count the number of each type of atom on both sides of the equation. Initially:
- Reactants:
- Al: 1
- H: 1
- Cl: 1
- Products:
- Al: 1
- H: 2
- Cl: 3
- Reactants:
-
Balance the chlorine (Cl) atoms by placing a coefficient of 3 in front of HCl: \[ \text{Al} + 3\text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2 \]
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Now count again:
- Reactants:
- Al: 1
- H: 3
- Cl: 3
- Products:
- Al: 1
- H: 2
- Cl: 3
- Reactants:
-
To balance hydrogen, place a coefficient of 3/2 (or 1.5) in front of Hâ‚‚: \[ \text{Al} + 3\text{HCl} \rightarrow \text{AlCl}_3 + \frac{3}{2}\text{H}_2 \] However, we prefer to use whole numbers, so we can multiply through by 2:
\[ 2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2 \]
The final balanced equation is: \[ \boxed{2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2} \]