Question

Evaluate the expression for x = 0.

–12x2 + 3x + 42 =


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Answered by GPT-4o mini
To evaluate the expression \(-12x^2 + 3x + 42\) for \(x = 0\), we substitute \(0\) into the expression:

\[
-12(0)^2 + 3(0) + 42
\]

Calculating each term:

1. \(-12(0)^2 = -12 \cdot 0 = 0\)
2. \(3(0) = 0\)
3. The constant \(42\) remains \(42\).

Now, combining all terms:

\[
0 + 0 + 42 = 42
\]

Thus, the value of the expression when \(x = 0\) is:

\[
\boxed{42}
\]
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