To solve the equation \((x + 12)^2 = 9\) using square roots, we can follow these steps:
- Take the square root of both sides:
\[ x + 12 = \pm 3 \]
- Now, we separate the two cases:
Case 1:
\[ x + 12 = 3 \] Subtracting 12 from both sides gives:
\[ x = 3 - 12 = -9 \]
Case 2:
\[ x + 12 = -3 \] Subtracting 12 from both sides gives:
\[ x = -3 - 12 = -15 \]
Therefore, the solutions to the equation \((x + 12)^2 = 9\) are:
\[ x = -9 \quad \text{and} \quad x = -15 \]
The solution set in set notation is:
\({-9, -15}\)
So the correct response is:
\({-9, -15}\)