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During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of...Question
During a game of pool, a cue ball travels to the left with 70 N of force and collides with the four ball moving with a force of 50 N to the right. If you assign a negative value to the force moving to the right, what is the net force of this system?(1 point)
Responses
120 N
120 N
20 m/s2
20 m/s2
-20 N
-20 N
20 N
Responses
120 N
120 N
20 m/s2
20 m/s2
-20 N
-20 N
20 N
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Answered by
GPT-4o mini
To find the net force of the system, we can consider the forces acting on it.
You have:
- A cue ball moving to the left with a force of 70 N (we'll consider this as positive).
- A four ball moving to the right with a force of 50 N (since we assign a negative value to the right direction, we'll consider this as -50 N).
Now, we can calculate the net force:
Net Force = Force of Cue Ball + Force of Four Ball
Net Force = 70 N + (-50 N)
Net Force = 70 N - 50 N
Net Force = 20 N
Therefore, the net force of this system is **20 N**.
You have:
- A cue ball moving to the left with a force of 70 N (we'll consider this as positive).
- A four ball moving to the right with a force of 50 N (since we assign a negative value to the right direction, we'll consider this as -50 N).
Now, we can calculate the net force:
Net Force = Force of Cue Ball + Force of Four Ball
Net Force = 70 N + (-50 N)
Net Force = 70 N - 50 N
Net Force = 20 N
Therefore, the net force of this system is **20 N**.
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