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Question


If △XYZ∼△AYB
, and YB = 26 ft half of the hypotenuse, YA = 14 ft half of the height and YZ = 92 ft which is the hypotenuse, then what is they length of YX¯¯¯¯¯¯¯¯
?



(1 point)
Responses

39.56 ft
39.56 ft

56.32 ft
56.32 ft

170.86 ft
170.86 ft

49.53 ft
49.53 ft
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Answer 1

To solve for the length of \( YX \) in the triangles \( \triangle XYZ \) and \( \triangle AYB \), we first need to use the properties of similar triangles. Since \( \triangle XYZ \sim \triangle AYB \), we can establish a relationship between their corresponding sides.

We're given:
- \( YB = 26 \) ft (half of the hypotenuse of \( \triangle AYB \))
- \( YA = 14 \) ft (half of the height of \( \triangle AYB \))
- \( YZ = 92 \) ft (hypotenuse of \( \triangle XYZ \))

From the information given, we can derive the full dimensions of \( \triangle AYB \):
- The full hypotenuse \( AB = 2 \times YB = 2 \times 26 \) ft = 52 ft.
- The full height \( A = 2 \times YA = 2 \times 14 \) ft = 28 ft.

Let’s denote:
- \( YX = x \)
- From similar triangles, we set up the ratio:

\[
\frac{YX}{YA} = \frac{YZ}{AB}
\]

Substituting the known values:

\[
\frac{x}{14} = \frac{92}{52}
\]

Cross-multiply to solve for \( x \):

\[
52x = 14 \times 92
\]
\[
52x = 1288
\]
\[
x = \frac{1288}{52}
\]
\[
x = 24.77 \text{ ft}
\]

Thus, the length of \( YX \) is approximately **24.77 ft**.

Since the choices provided do not include this answer, there may be an error in the values provided or the expected answer. None of the response options match the calculation.

If you believe there could be additional conditions or specific rounding in the provided answers, please recheck the scenario. If the values are correct, my calculations seem to indicate \( YX \approx 24.77 \) ft.