For the questions you've provided, I'll summarize the calculations for each one.
Question 1
A) To dilate a point (x, y) with respect to the origin (0, 0) by a magnitude of k, we use the formula: \[ (kx, ky) \]
Let’s assume the original vertices of triangle ABC are given as follows based on the options:
- A(0,0)
- B(1,2)
- C(3,0)
To find A', B', and C' for a magnitude of 3:
- A′(0, 0) = (30, 30) = (0, 0)
- B′(1, 2) = (31, 32) = (3, 6)
- C′(3, 0) = (33, 30) = (9, 0)
So, the final vertices after dilation would be: \[ A′(0, 0), B′(3, 6), C′(9, 0) \] None of the options provided seem to match exactly with assumed points. Please double-check the initial coordinates.
Question 2
A) For the dilation, the magnitude can be found by comparing the corresponding points of the original polygon ABCD and the dilated polygon A'B'C'D'. If polygon ABCD has dimensions or coordinates and is dilated to A'B'C'D', we would calculate the ratio between a corresponding pair of vertices (e.g., distance from the origin). If the coordinates are given in the image, check the ratio of their respective distances from the origin.
Without specific coordinates, this cannot be calculated accurately.
Question 3
A) Again, if you can identify the original vertices of parallelogram ABCD and the dilated vertices A'B'C'D', you calculate the same way as in Question 2 using the distance from the origin.
Question 4
A) When dilating triangle XYZ about the center of dilation (4,7) with a magnitude of \( \frac{1}{2} \): For a point P(x, y), the new point after dilation is calculated as follows: \[ P'(x', y') = \left( (1-k)x + kx_c, (1-k)y + ky_c \right) \] where \( (x_c, y_c) \) is the center of dilation.
For triangle XYZ:
- X(0, 4): \[ X' = \left( (1-\frac{1}{2}) * 0 + \frac{1}{2} * 4, (1-\frac{1}{2}) * 4 + \frac{1}{2} * 7 \right) = (2, 5.5) \]
- Y(2, 0): \[ Y' = \left( (1-\frac{1}{2}) * 2 + \frac{1}{2} * 4, (1-\frac{1}{2}) * 0 + \frac{1}{2} * 7 \right) = (3, 3.5) \]
- Z(4, 7): \[ Z' = \left( (1-\frac{1}{2}) * 4 + \frac{1}{2} * 4, (1-\frac{1}{2}) * 7 + \frac{1}{2} * 7 \right) = (4, 7) \]
Thus, final dilated points are: \[ X′(2, 5.5), Y′(3, 3.5), Z′(4, 7) \]
Question 5
A) With duplication center at (-2,-1) and dilation magnitude of 2: Using the same formula: \[ A' = \left( (1 - k)x + kx_c, (1 - k)y + ky_c \right) \] Where k is 2. Let’s say point A is \( x_a, y_a \) (You did not specify, so please confirm the point). The old A coordinates should follow: \[ A' = \left( (1-2)x_a + 2*-2, (1-2)y_a + 2*-1 \right) \]
From the options: If A is at (-1, 2): \[ A' = \left( (-3 + 4), (-3 + 2) \right) = (1, -1) \]
Check points accordingly using the formula.
Please give me further details or clarify any coordinates for more accurate answers.