To determine a viable solution for the number of robotics kits and chemistry sets Cindy can purchase, we need to set up and solve the equation based on her total winnings:
Let:
- \( y \) = number of robotics kits
- \( x \) = number of chemistry sets
The cost of a robotics kit is $10.00 and the cost of a chemistry set is $8.00, with a total budget of $50.00. The equation can be represented as:
\[ 10y + 8x = 50 \]
We'll analyze the given response options to see if they satisfy this equation.
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(3, 2.6): \[ 10(3) + 8(2.6) = 30 + 20.8 = 50.8 \quad (\text{not a solution}) \]
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(5, 1): \[ 10(5) + 8(1) = 50 + 8 = 58 \quad (\text{not a solution}) \]
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(−5, 9): \[ 10(-5) + 8(9) = -50 + 72 = 22 \quad (\text{not a solution}) \]
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(0, 5): \[ 10(0) + 8(5) = 0 + 40 = 40 \quad (\text{not a solution}) \]
None of the given options satisfy the equation \( 10y + 8x = 50 \).
However, let's further clarify criteria for solutions. Since \( y \) and \( x \) must be non-negative integers (as you can't purchase a negative quantity or fractional kits), none of the provided answers fit this criterion.
To check for valid integer solutions:
- If Cindy bought only robotics kits (\( x = 0 \)): \[ 10y = 50 \quad \Rightarrow \quad y = 5 \]
- If Cindy bought only chemistry sets (\( y = 0 \)): \[ 8x = 50 \quad \Rightarrow \quad x = 6.25 \quad (\text{not an integer}) \]
Thus, suitable combinations could be (for integer values):
- (5, 0): 5 robotics kits and 0 chemistry sets.
- (4, 1): 4 robotics kits and 1 chemistry set.
- (3, 2): 3 robotics kits and 2 chemistry sets.
- (2, 3): 2 robotics kits and 3 chemistry sets.
- (1, 4): 1 robotics kit and 4 chemistry sets.
- (0, 5): 0 robotic kits and 5 chemistry sets.
The integers that satisfy the budget will need to be analyzed from these possible combinations. But again, from the provided options, none are viable solutions.