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Which table of values represents a linear function? A xx yy minus, 2−2 00 11 22 55 44 88 66 B xx yy 11 22 22 00 33 minus, 2−2 5...Question
Which table of values represents a linear function?
A
xx yy
minus, 2−2 00
11 22
55 44
88 66
B
xx yy
11 22
22 00
33 minus, 2−2
55 minus, 5−5
C
xx yy
minus, 5−5 minus, 6−6
minus, 1−1 00
33 66
66 99
D
xx yy
minus, 5−5 minus, 6−6
minus, 3−3 minus, 4−4
00 minus, 1−1
22 11
Your Answer
D
D
Unsubmit Answer
A
xx yy
minus, 2−2 00
11 22
55 44
88 66
B
xx yy
11 22
22 00
33 minus, 2−2
55 minus, 5−5
C
xx yy
minus, 5−5 minus, 6−6
minus, 1−1 00
33 66
66 99
D
xx yy
minus, 5−5 minus, 6−6
minus, 3−3 minus, 4−4
00 minus, 1−1
22 11
Your Answer
D
D
Unsubmit Answer
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which table of values represents a linear function, we need to check if the y-values change at a constant rate as the x-values change. This means for any two points, the change in y divided by the change in x (also known as the slope) should be constant.
Let's analyze each table:
**A:**
- (−2, 0), (1, 2), (5, 4), (8, 6)
- Changes in x: 1 - (−2) = 3, 5 - 1 = 4, 8 - 5 = 3
- Changes in y: 2 - 0 = 2, 4 - 2 = 2, 6 - 4 = 2
- The change in y is constant (2) but the change in x is not constant. Thus, this is **not linear**.
**B:**
- (1, 2), (2, 0), (3, −2), (5, −5)
- Changes in x: 2 - 1 = 1, 3 - 2 = 1, 5 - 3 = 2
- Changes in y: 0 - 2 = −2, −2 - 0 = −2, −5 - (−2) = −3
- The change in y is not constant, so this is also **not linear**.
**C:**
- (−5, −6), (−1, 0), (3, 6), (6, 9)
- Changes in x: (−1) - (−5) = 4, 3 - (−1) = 4, 6 - 3 = 3
- Changes in y: 0 - (−6) = 6, 6 - 0 = 6, 9 - 6 = 3
- The change in y is not constant; therefore, this is **not linear**.
**D:**
- (−5, −6), (−3, −4), (0, −1), (2, 11)
- Changes in x: (−3) - (−5) = 2, 0 - (−3) = 3, 2 - 0 = 2
- Changes in y: (−4) - (−6) = 2, (−1) - (−4) = 3, 11 - (−1) = 12
- The change in y is also not constant across the values, thus this is **not linear**.
Based on the analysis, none of the provided tables of values represent a linear function. If you have additional tables or values to consider, please share them, and I'll be happy to help.
Let's analyze each table:
**A:**
- (−2, 0), (1, 2), (5, 4), (8, 6)
- Changes in x: 1 - (−2) = 3, 5 - 1 = 4, 8 - 5 = 3
- Changes in y: 2 - 0 = 2, 4 - 2 = 2, 6 - 4 = 2
- The change in y is constant (2) but the change in x is not constant. Thus, this is **not linear**.
**B:**
- (1, 2), (2, 0), (3, −2), (5, −5)
- Changes in x: 2 - 1 = 1, 3 - 2 = 1, 5 - 3 = 2
- Changes in y: 0 - 2 = −2, −2 - 0 = −2, −5 - (−2) = −3
- The change in y is not constant, so this is also **not linear**.
**C:**
- (−5, −6), (−1, 0), (3, 6), (6, 9)
- Changes in x: (−1) - (−5) = 4, 3 - (−1) = 4, 6 - 3 = 3
- Changes in y: 0 - (−6) = 6, 6 - 0 = 6, 9 - 6 = 3
- The change in y is not constant; therefore, this is **not linear**.
**D:**
- (−5, −6), (−3, −4), (0, −1), (2, 11)
- Changes in x: (−3) - (−5) = 2, 0 - (−3) = 3, 2 - 0 = 2
- Changes in y: (−4) - (−6) = 2, (−1) - (−4) = 3, 11 - (−1) = 12
- The change in y is also not constant across the values, thus this is **not linear**.
Based on the analysis, none of the provided tables of values represent a linear function. If you have additional tables or values to consider, please share them, and I'll be happy to help.
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