Given h, of, x, equals, 3, x, plus, 4h(x)=3x+4, find h, of, minus, 1h(−1).

To find \( h(-1) \) given the function \( h(x) = 3x + 4 \), we simply need to substitute \(-1\) for \(x\) in the function.

Starting with the function:

\[ h(x) = 3x + 4 \]

Now substitute \(-1\) for \(x\):

\[ h(-1) = 3(-1) + 4 \]

Calculating this:

\[ h(-1) = -3 + 4 = 1 \]

Therefore, \( h(-1) = 1 \).