Fill in the blanks!

A basketball has a radius of 5 inches. Approximately how much air does it take to fill the bastetball?

- Sphere V = 4/3 pi r^(3)

V = 4/3 pi r^(3)
V = 4/3 pi(5)^(3)
V = _ (4/3) pi
V ~ _ in.^(3)

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
2 hours ago

To fill in the blanks, we can calculate the volume of the basketball using the formula for the volume of a sphere.

Given the radius \( r = 5 \) inches:

  1. First, we calculate \( (5)^3 \): \[ (5)^3 = 125 \]

  2. Then we substitute this value into the volume formula: \[ V = \frac{4}{3} \pi (5)^{3} = \frac{4}{3} \pi (125) \] \[ V = \frac{500}{3} \pi \]

  3. Next, we can approximate \( \pi \approx 3.14 \): \[ V \approx \frac{500}{3} \times 3.14 \] \[ V \approx \frac{1570}{3} \approx 523.33 \text{ in}^3 \]

Now, filling in the blanks:

  • \( V = \frac{500}{3} \pi \)
  • \( V \approx 523.33 \) in\(^3\)

Final answer:

  • V = \( \frac{500}{3} \pi \)
  • V ~ 523.33 in.\(^3\)