Question

Fill in the blanks!
A basketball has a radius of 5 inches. Approximately how much air does it take to fill the bastetball?

- Sphere V = 4/3 pi r^(3)

V = 4/3 pi r^(3)
V = 4/3 pi(5)^(3)
V = _ (4/3) pi
V ~ _ in.^(3)

Answer 1

To fill in the blanks, we can calculate the volume of the basketball using the formula for the volume of a sphere.

Given the radius \( r = 5 \) inches:

1. First, we calculate \( (5)^3 \):
\[
(5)^3 = 125
\]

2. Then we substitute this value into the volume formula:
\[
V = \frac{4}{3} \pi (5)^{3} = \frac{4}{3} \pi (125)
\]
\[
V = \frac{500}{3} \pi
\]

3. Next, we can approximate \( \pi \approx 3.14 \):
\[
V \approx \frac{500}{3} \times 3.14
\]
\[
V \approx \frac{1570}{3} \approx 523.33 \text{ in}^3
\]

Now, filling in the blanks:

- \( V = \frac{500}{3} \pi \)
- \( V \approx 523.33 \) in\(^3\)

Final answer:
- V = \( \frac{500}{3} \pi \)
- V ~ 523.33 in.\(^3\)