Asked by blobby
Find the sum of the interior angles of a nonagon (9-sided polygon).
(1 point)
Responses
The sum of the interior angles of a nonagon is 1,620°
.
The sum of the interior angles of a nonagon is 1,620 degrees .
The sum of the interior angles of a nonagon is 1,260°
.
The sum of the interior angles of a nonagon is 1,260 degrees .
The sum of the interior angles of a nonagon is 1,980°
.
The sum of the interior angles of a nonagon is 1,980 degrees .
The sum of the interior angles of a nonagon is 187°
.
(1 point)
Responses
The sum of the interior angles of a nonagon is 1,620°
.
The sum of the interior angles of a nonagon is 1,620 degrees .
The sum of the interior angles of a nonagon is 1,260°
.
The sum of the interior angles of a nonagon is 1,260 degrees .
The sum of the interior angles of a nonagon is 1,980°
.
The sum of the interior angles of a nonagon is 1,980 degrees .
The sum of the interior angles of a nonagon is 187°
.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the sum of the interior angles of a nonagon (a 9-sided polygon), you can use the formula:
\[
\text{Sum of interior angles} = (n - 2) \times 180°
\]
where \(n\) is the number of sides.
For a nonagon, \(n = 9\):
\[
\text{Sum of interior angles} = (9 - 2) \times 180° = 7 \times 180° = 1260°
\]
Thus, the sum of the interior angles of a nonagon is **1,260 degrees**.
\[
\text{Sum of interior angles} = (n - 2) \times 180°
\]
where \(n\) is the number of sides.
For a nonagon, \(n = 9\):
\[
\text{Sum of interior angles} = (9 - 2) \times 180° = 7 \times 180° = 1260°
\]
Thus, the sum of the interior angles of a nonagon is **1,260 degrees**.
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