Question
Which table of values represents a linear function?
A
xx yy
minus, 2−2 66
22 44
55 22
88 00
B
xx yy
minus, 9−9 minus, 8−8
minus, 3−3 minus, 4−4
33 minus, 1−1
99 22
C
xx yy
minus, 5−5 minus, 7−7
minus, 2−2 minus, 6−6
11 minus, 4−4
44 minus, 2−2
D
xx yy
minus, 5−5 44
minus, 2−2 11
11 minus, 2−2
44 minus, 5−5
A
xx yy
minus, 2−2 66
22 44
55 22
88 00
B
xx yy
minus, 9−9 minus, 8−8
minus, 3−3 minus, 4−4
33 minus, 1−1
99 22
C
xx yy
minus, 5−5 minus, 7−7
minus, 2−2 minus, 6−6
11 minus, 4−4
44 minus, 2−2
D
xx yy
minus, 5−5 44
minus, 2−2 11
11 minus, 2−2
44 minus, 5−5
Answers
Answered by
GPT-4o mini
To determine which table of values represents a linear function, we need to check if the change in \(y\) (the dependent variable) is consistent for a consistent change in \(x\) (the independent variable). This means examining whether the slopes between consecutive points are the same.
Let's analyze each table individually:
### Table A
```
x | y
---------
-2 | 6
2 | 4
5 | 2
8 | 0
```
Calculating the differences in \(y\) for each pair of \(x\):
- From \(-2\) to \(2\): \(4 - 6 = -2\)
- From \(2\) to \(5\): \(2 - 4 = -2\)
- From \(5\) to \(8\): \(0 - 2 = -2\)
The slope is constant \(-2\). **Table A represents a linear function.**
### Table B
```
x | y
---------
-9 | -8
-3 | -4
3 | -1
9 | 2
```
Calculating the differences in \(y\):
- From \(-9\) to \(-3\): \(-4 - (-8) = 4\)
- From \(-3\) to \(3\): \(-1 - (-4) = 3\)
- From \(3\) to \(9\): \(2 - (-1) = 3\)
The changes are \(4\), \(3\), and \(3\). The slope is not constant. **Table B does not represent a linear function.**
### Table C
```
x | y
---------
-5 | -7
-2 | -6
1 | -4
4 | -2
```
Calculating the differences in \(y\):
- From \(-5\) to \(-2\): \(-6 - (-7) = 1\)
- From \(-2\) to \(1\): \(-4 - (-6) = 2\)
- From \(1\) to \(4\): \(-2 - (-4) = 2\)
The changes are \(1\), \(2\), \(2\). The slope is not constant. **Table C does not represent a linear function.**
### Table D
```
x | y
---------
-5 | 4
-2 | 1
1 | -2
4 | -5
```
Calculating the differences in \(y\):
- From \(-5\) to \(-2\): \(1 - 4 = -3\)
- From \(-2\) to \(1\): \(-2 - 1 = -3\)
- From \(1\) to \(4\): \(-5 - (-2) = -3\)
The slope is constant \(-3\). **Table D represents a linear function.**
### Summary
Only Tables A and D represent linear functions.
Let's analyze each table individually:
### Table A
```
x | y
---------
-2 | 6
2 | 4
5 | 2
8 | 0
```
Calculating the differences in \(y\) for each pair of \(x\):
- From \(-2\) to \(2\): \(4 - 6 = -2\)
- From \(2\) to \(5\): \(2 - 4 = -2\)
- From \(5\) to \(8\): \(0 - 2 = -2\)
The slope is constant \(-2\). **Table A represents a linear function.**
### Table B
```
x | y
---------
-9 | -8
-3 | -4
3 | -1
9 | 2
```
Calculating the differences in \(y\):
- From \(-9\) to \(-3\): \(-4 - (-8) = 4\)
- From \(-3\) to \(3\): \(-1 - (-4) = 3\)
- From \(3\) to \(9\): \(2 - (-1) = 3\)
The changes are \(4\), \(3\), and \(3\). The slope is not constant. **Table B does not represent a linear function.**
### Table C
```
x | y
---------
-5 | -7
-2 | -6
1 | -4
4 | -2
```
Calculating the differences in \(y\):
- From \(-5\) to \(-2\): \(-6 - (-7) = 1\)
- From \(-2\) to \(1\): \(-4 - (-6) = 2\)
- From \(1\) to \(4\): \(-2 - (-4) = 2\)
The changes are \(1\), \(2\), \(2\). The slope is not constant. **Table C does not represent a linear function.**
### Table D
```
x | y
---------
-5 | 4
-2 | 1
1 | -2
4 | -5
```
Calculating the differences in \(y\):
- From \(-5\) to \(-2\): \(1 - 4 = -3\)
- From \(-2\) to \(1\): \(-2 - 1 = -3\)
- From \(1\) to \(4\): \(-5 - (-2) = -3\)
The slope is constant \(-3\). **Table D represents a linear function.**
### Summary
Only Tables A and D represent linear functions.
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