Question
Factor the trinomial:
5, x, squared, plus, 13, x, plus, 6
5x
2
+13x+6
5, x, squared, plus, 13, x, plus, 6
5x
2
+13x+6
Answers
Answered by
GPT-4o mini
To factor the trinomial \( 5x^2 + 13x + 6 \), we will look for two numbers that multiply to \( 5 \times 6 = 30 \) (the product of the coefficient of \( x^2 \) and the constant term) and add up to \( 13 \) (the coefficient of \( x \)).
The numbers that work are \( 3 \) and \( 10 \), since:
- \( 3 \times 10 = 30 \)
- \( 3 + 10 = 13 \)
Now, we can rewrite the middle term (the \( 13x \)) using these two numbers:
\[
5x^2 + 3x + 10x + 6
\]
Next, we can group the terms:
\[
(5x^2 + 3x) + (10x + 6)
\]
Now, we factor by grouping:
1. Factor out \( x \) from the first group and \( 2 \) from the second group:
\[
x(5x + 3) + 2(5x + 3)
\]
2. Now, we can factor out the common binomial \( (5x + 3) \):
\[
(5x + 3)(x + 2)
\]
Thus, the factorization of the trinomial \( 5x^2 + 13x + 6 \) is:
\[
\boxed{(5x + 3)(x + 2)}
\]
The numbers that work are \( 3 \) and \( 10 \), since:
- \( 3 \times 10 = 30 \)
- \( 3 + 10 = 13 \)
Now, we can rewrite the middle term (the \( 13x \)) using these two numbers:
\[
5x^2 + 3x + 10x + 6
\]
Next, we can group the terms:
\[
(5x^2 + 3x) + (10x + 6)
\]
Now, we factor by grouping:
1. Factor out \( x \) from the first group and \( 2 \) from the second group:
\[
x(5x + 3) + 2(5x + 3)
\]
2. Now, we can factor out the common binomial \( (5x + 3) \):
\[
(5x + 3)(x + 2)
\]
Thus, the factorization of the trinomial \( 5x^2 + 13x + 6 \) is:
\[
\boxed{(5x + 3)(x + 2)}
\]
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