Question

Find the slope of the line passing through (6, -1( and (7, 3). Let (x1, y1) = (6, -1) and (x2, y2) = (7, 3). List the coordinates, fill in the slope formula, then simplify

x1 = __
x2 = __
y1 = __
y2 = __

Use the slope formula: slope = y2 - y1 / x2 - x1

Answer 1

Let's determine the coordinates and use the slope formula.

Given the points:
- \((x_1, y_1) = (6, -1)\)
- \((x_2, y_2) = (7, 3)\)

Now we can fill in the values:

- \(x_1 = 6\)
- \(x_2 = 7\)
- \(y_1 = -1\)
- \(y_2 = 3\)

Now, let's use the slope formula:

\[
\text{slope} = \frac{y_2 - y_1}{x_2 - x_1}
\]

Substituting the values:

\[
\text{slope} = \frac{3 - (-1)}{7 - 6}
\]

Simplifying the numerator:

\[
3 - (-1) = 3 + 1 = 4
\]

Thus, we have:

\[
\text{slope} = \frac{4}{7 - 6} = \frac{4}{1}
\]

So, the slope simplifies to:

\[
\text{slope} = 4
\]

Therefore, the slope of the line passing through the points (6, -1) and (7, 3) is \(4\).