a line with a slope of m=-1/2 passes through the point (4,6) what is the equation of the line in standard form?

To find the equation of the line in standard form \(Ax + By = C\) with a slope of \(m = -\frac{1}{2}\) that passes through the point \((4, 6)\), we can use the slope-intercept form first and then convert it.

1. Start with the slope-intercept form: \[ y = mx + b \] where \(m\) is the slope and \(b\) is the y-intercept. We know the slope \(m = -\frac{1}{2}\):

   \[ y = -\frac{1}{2}x + b \]

2. Substitute the point (4, 6) into the equation to find \(b\):

   \[ 6 = -\frac{1}{2}(4) + b \]

   \[ 6 = -2 + b \]

   \[ b = 6 + 2 = 8 \]

   So, the equation in slope-intercept form is:

   \[ y = -\frac{1}{2}x + 8 \]

3. Convert to standard form \(Ax + By = C\):

   To convert, we can rearrange the equation:

   \[ \frac{1}{2}x + y = 8 \]

   To eliminate the fraction, multiply everything by 2:

   \[ x + 2y = 16 \]

So the equation of the line in standard form is:

\[ x + 2y = 16 \]

Thus, \(x + ?y = ?\) is \(x + 2y = 16\). The values are \(? = 2\) and the constant \(? = 16\).