Asked by Ashh
Jake's grandparents get him a puppy for his thirteenth birthday, and he names the puppy Ruby. Jake does a good job taking care of Ruby, and she's growing so fast!
This table shows the relationship between Ruby's age (in months), x, and her weight (in pounds), y.
x (months) y (pounds)
2 6.5
4 12
6 17.5
10 28.5
According to the values in the table, do x and y have a proportional relationship?
yes
no
This table shows the relationship between Ruby's age (in months), x, and her weight (in pounds), y.
x (months) y (pounds)
2 6.5
4 12
6 17.5
10 28.5
According to the values in the table, do x and y have a proportional relationship?
yes
no
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine if there is a proportional relationship between Ruby's age (x) and her weight (y), we need to check if the ratio of \( y \) to \( x \) (weight to age) is constant for all the given values.
Calculating the ratios:
1. For \( x = 2 \):
\[
\frac{y}{x} = \frac{6.5}{2} = 3.25
\]
2. For \( x = 4 \):
\[
\frac{y}{x} = \frac{12}{4} = 3
\]
3. For \( x = 6 \):
\[
\frac{y}{x} = \frac{17.5}{6} \approx 2.917
\]
4. For \( x = 10 \):
\[
\frac{y}{x} = \frac{28.5}{10} = 2.85
\]
The ratios are:
- \( \frac{6.5}{2} = 3.25 \)
- \( \frac{12}{4} = 3 \)
- \( \frac{17.5}{6} \approx 2.917 \)
- \( \frac{28.5}{10} = 2.85 \)
Since the ratios are not constant, we can conclude that \( x \) and \( y \) do not have a proportional relationship.
So the answer is **no**.
Calculating the ratios:
1. For \( x = 2 \):
\[
\frac{y}{x} = \frac{6.5}{2} = 3.25
\]
2. For \( x = 4 \):
\[
\frac{y}{x} = \frac{12}{4} = 3
\]
3. For \( x = 6 \):
\[
\frac{y}{x} = \frac{17.5}{6} \approx 2.917
\]
4. For \( x = 10 \):
\[
\frac{y}{x} = \frac{28.5}{10} = 2.85
\]
The ratios are:
- \( \frac{6.5}{2} = 3.25 \)
- \( \frac{12}{4} = 3 \)
- \( \frac{17.5}{6} \approx 2.917 \)
- \( \frac{28.5}{10} = 2.85 \)
Since the ratios are not constant, we can conclude that \( x \) and \( y \) do not have a proportional relationship.
So the answer is **no**.
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