A coordinate plane with a line passing through (0, negative 5) and (3, 0).

What is the equation of the graphed line written in standard form?

3x + y = –5
x + 3y = –5
3x – 5y = –15
5x – 3y = 15

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
3 hours ago

To find the equation of the line passing through the points (0, -5) and (3, 0), we can start by calculating the slope (m) of the line. The slope is given by the formula:

\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

Using the points (0, -5) and (3, 0):

  • \( x_1 = 0, y_1 = -5 \)
  • \( x_2 = 3, y_2 = 0 \)

The slope becomes:

\[ m = \frac{0 - (-5)}{3 - 0} = \frac{5}{3} \]

Now that we have the slope, we can use the point-slope form of the equation of a line, which is:

\[ y - y_1 = m(x - x_1) \]

Using the point (0, -5):

\[ y - (-5) = \frac{5}{3}(x - 0) \]

Simplifying this gives:

\[ y + 5 = \frac{5}{3}x \]

Subtracting 5 from both sides:

\[ y = \frac{5}{3}x - 5 \]

To convert this equation to standard form \(Ax + By = C\), we can multiply everything by 3 to eliminate the fraction:

\[ 3y = 5x - 15 \]

Rearranging it gives:

\[ -5x + 3y = -15 \]

To put it in the standard form \(Ax + By = C\) with A positive, multiply the entire equation by -1:

\[ 5x - 3y = 15 \]

Thus, the equation of the line in standard form is:

\[ 5x - 3y = 15 \]

So the correct answer is:

5x - 3y = 15