Question

A coin rests 15 cm away from the center of a turntable. The turntable starts to rotate at an angular acceleration of .8 rad/s^2 and after 7 seconds it slides off. What is the coefficient of static friction between the coin and the surface?

Just give me step by step on how to solve this problem.
It starts sliding when the static friction force reaches its maximum value. Its maximum value is Us*M*g.
Us is the static coefficeint you want to determine

After 7 seconds, the angular velocity is 5.6 rad/s and the centripetal acceleration is
Rw^2 = -.15*(5.6)^2 = 4.7 m/s^2.
There is also continuing tangential acceleration of R*alpha = 0.12 m/s^2 The vector-sum acceleration is
4.701 m/s^2, so you can ignore the tangential acceleration effect.

Us*M*g = M R w^2
Us = R w^2/g = 4.7/9.8 = 0.48

Related Questions

if i flip a coin, will the coin stop moving upwards first before it starts to move down? in other wo... a coin rests on a book. the book tilts until the coin just begins to move. the angle is 17 degrees... a sliver coin and a gold coin each have a mass of exactly 6.6 grams the specific heat of sliver is 0... A coin rests 18.0 cm from the center of a turntable. The coefficient of static friction between the... A coin rests on a record 0.15 m from its center. The record turns on a turntable that rotates at var... Which of the following rests lasts the same amount of time as a quarter note? (1 point) Responses... A coin flip: A fair coin is tossed three times. The outcomes of the three tosses are recorded. Round... flips a coin 80 times. The coin lands heads up 48 times and tails up 32 times. Complete each stateme...