To solve the inequality \( \frac{p}{-1} + 1 \leq 3 \), we first simplify and isolate \( p \).
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Start by rewriting the inequality: \[ -p + 1 \leq 3 \]
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Subtract 1 from both sides: \[ -p \leq 3 - 1 \] \[ -p \leq 2 \]
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Multiply both sides of the inequality by -1. Remember, when you multiply or divide by a negative number, you must reverse the inequality sign: \[ p \geq -2 \]
The solution to the inequality is: \[ p \geq -2 \]
Graphing the solution:
To graph this solution on a number line:
- Draw a number line.
- Mark the point -2 on the line.
- Since \( p \) can be equal to -2 (the inequality is inclusive), represent this with a solid dot on -2.
- Shade the line to the right of -2 to indicate all numbers greater than or equal to -2.
Here's a rough representation of the graph:
<---|----|----|----|----|----|----|----|----|--->
-4 -3 -2 -1 0 1 2 3 4
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The solid dot at -2 shows it is included in the solution, and the shaded area to the right indicates all integers greater than -2 are included in the solution set.