Question
Which equation represents the line that passes through (–6, 7) and (–3, 6)?
y = –y equals negative StartFraction one-third EndFraction x plus 5.x + 9
y = –y equals negative StartFraction one-third EndFraction x plus 5.x + 5
y = –3x – 11y
y = –3x + 25
y = –y equals negative StartFraction one-third EndFraction x plus 5.x + 9
y = –y equals negative StartFraction one-third EndFraction x plus 5.x + 5
y = –3x – 11y
y = –3x + 25
Answers
Answered by
GPT-4o mini
To find the equation of the line that passes through the points \((-6, 7)\) and \((-3, 6)\), we first need to determine the slope (m) of the line using the formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Here, \((x_1, y_1) = (-6, 7)\) and \((x_2, y_2) = (-3, 6)\):
\[
m = \frac{6 - 7}{-3 + 6} = \frac{-1}{3} = -\frac{1}{3}
\]
Now we can use the point-slope form of the line equation:
\[
y - y_1 = m(x - x_1)
\]
Substituting one of the points, say \((-6, 7)\), and the slope \(-\frac{1}{3}\):
\[
y - 7 = -\frac{1}{3}(x + 6)
\]
Now, let's rearrange this into slope-intercept form (y = mx + b):
\[
y - 7 = -\frac{1}{3}x - 2
\]
\[
y = -\frac{1}{3}x + 5
\]
Now, looking at your options, the equivalent equation is:
\[
y = -\frac{1}{3}x + 5
\]
Therefore, the correct answer is:
**y = –y equals negative StartFraction one-third EndFraction x plus 5.**
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Here, \((x_1, y_1) = (-6, 7)\) and \((x_2, y_2) = (-3, 6)\):
\[
m = \frac{6 - 7}{-3 + 6} = \frac{-1}{3} = -\frac{1}{3}
\]
Now we can use the point-slope form of the line equation:
\[
y - y_1 = m(x - x_1)
\]
Substituting one of the points, say \((-6, 7)\), and the slope \(-\frac{1}{3}\):
\[
y - 7 = -\frac{1}{3}(x + 6)
\]
Now, let's rearrange this into slope-intercept form (y = mx + b):
\[
y - 7 = -\frac{1}{3}x - 2
\]
\[
y = -\frac{1}{3}x + 5
\]
Now, looking at your options, the equivalent equation is:
\[
y = -\frac{1}{3}x + 5
\]
Therefore, the correct answer is:
**y = –y equals negative StartFraction one-third EndFraction x plus 5.**