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Original Question
solve the inequality and graph the solution m < 6 + 3Asked by Ashh
Solve the inequality and graph the solution.
42≤26+8m
42≤26+8m
Answers
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Answered by
GPT-4o mini
To solve the inequality \(42 \leq 26 + 8m\), we will isolate \(m\).
1. Subtract 26 from both sides:
\[
42 - 26 \leq 8m
\]
\[
16 \leq 8m
\]
2. Next, divide both sides by 8:
\[
\frac{16}{8} \leq m
\]
\[
2 \leq m
\]
This can be rewritten as:
\[
m \geq 2
\]
The solution to the inequality is \(m \geq 2\).
### Graphing the Solution
When graphing this inequality on a number line:
- Place an open circle (or a filled circle, depending on your notation) at 2 to indicate that \(m\) is included in the solution (since it is greater than or equal to).
- Shade the line to the right of 2 to represent all values of \(m\) that are greater than or equal to 2.
Here’s how the number line would look:
```
<---|---|---|---|---|---|---|---|---|--->
0 1 2 3 4 5 6 7 8
●================>
```
The filled circle at 2 indicates that 2 is included in the solution, and the shaded area to the right indicates that all greater values are included.
1. Subtract 26 from both sides:
\[
42 - 26 \leq 8m
\]
\[
16 \leq 8m
\]
2. Next, divide both sides by 8:
\[
\frac{16}{8} \leq m
\]
\[
2 \leq m
\]
This can be rewritten as:
\[
m \geq 2
\]
The solution to the inequality is \(m \geq 2\).
### Graphing the Solution
When graphing this inequality on a number line:
- Place an open circle (or a filled circle, depending on your notation) at 2 to indicate that \(m\) is included in the solution (since it is greater than or equal to).
- Shade the line to the right of 2 to represent all values of \(m\) that are greater than or equal to 2.
Here’s how the number line would look:
```
<---|---|---|---|---|---|---|---|---|--->
0 1 2 3 4 5 6 7 8
●================>
```
The filled circle at 2 indicates that 2 is included in the solution, and the shaded area to the right indicates that all greater values are included.
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