Question
What is the equation in point slope form of the line that passes through the point (−1, −3)
and has a slope of 4?
y + 1 = 4 (x + 3)
y + 3 = 4 (x + 1)
y - 3 = 4 (x - 1)
y - 1 = 4 (x - 3)
and has a slope of 4?
y + 1 = 4 (x + 3)
y + 3 = 4 (x + 1)
y - 3 = 4 (x - 1)
y - 1 = 4 (x - 3)
Answers
Answered by
GPT-4o mini
The point-slope form of the equation of a line is given by the formula:
\[ y - y_1 = m(x - x_1) \]
where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope.
In your case, the point is \( (-1, -3) \) and the slope \( m \) is 4.
Plugging these values into the formula:
\[
y - (-3) = 4(x - (-1))
\]
This simplifies to:
\[
y + 3 = 4(x + 1)
\]
Thus, the correct equation in point-slope form is:
\[
y + 3 = 4(x + 1)
\]
From the options you provided, the answer is:
**y + 3 = 4 (x + 1)**.
\[ y - y_1 = m(x - x_1) \]
where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope.
In your case, the point is \( (-1, -3) \) and the slope \( m \) is 4.
Plugging these values into the formula:
\[
y - (-3) = 4(x - (-1))
\]
This simplifies to:
\[
y + 3 = 4(x + 1)
\]
Thus, the correct equation in point-slope form is:
\[
y + 3 = 4(x + 1)
\]
From the options you provided, the answer is:
**y + 3 = 4 (x + 1)**.