Add: (4d−3)+(12d+4)

To add the expressions \( (4d - 3) + (12d + 4) \), you can combine like terms.

1. Add the coefficients of \( d \): \[ 4d + 12d = 16d \]

2. Add the constant terms: \[ -3 + 4 = 1 \]

Putting it all together, the sum is: \[ 16d + 1 \]

So, \((4d - 3) + (12d + 4) = 16d + 1\).