To add the expressions \( \frac{1}{2} ( x + 4 ) + \frac{1}{4} ( 4x - 2 ) \), we first simplify each term separately.
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Simplifying \( \frac{1}{2} ( x + 4 ) \): \[ \frac{1}{2} ( x + 4 ) = \frac{1}{2} x + \frac{1}{2} \cdot 4 = \frac{1}{2} x + 2 \]
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Simplifying \( \frac{1}{4} ( 4x - 2 ) \): \[ \frac{1}{4} ( 4x - 2 ) = \frac{1}{4} \cdot 4x - \frac{1}{4} \cdot 2 = x - \frac{1}{2} \]
Now, we can add the two results together: \[ \left( \frac{1}{2} x + 2 \right) + \left( x - \frac{1}{2} \right) \]
Combine like terms:
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The \( x \) terms: \[ \frac{1}{2} x + x = \frac{1}{2} x + \frac{2}{2} x = \frac{3}{2} x \]
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The constant terms: \[ 2 - \frac{1}{2} = 2 - 0.5 = 1.5 = \frac{3}{2} \]
Therefore, the combined result is: \[ \frac{3}{2} x + \frac{3}{2} \]
To express this in mixed number form, we can factor out \( \frac{3}{2} \): \[ \frac{3}{2} ( x + 1 ) \]
Thus, the final answer is: \[ \frac{3}{2} ( x + 1 ) \]