Question
                If  ΔPRQ
has ∠P=30
and ∠R=127
and ΔFGH
has ∠H=30
and ∠G=23
, what criterion has been met to prove the triangles similar?(1 point)
Responses
SSS
SSS
ASA
ASA
SAS
SAS
AA
            
        has ∠P=30
and ∠R=127
and ΔFGH
has ∠H=30
and ∠G=23
, what criterion has been met to prove the triangles similar?(1 point)
Responses
SSS
SSS
ASA
ASA
SAS
SAS
AA
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To determine if the triangles ΔPRQ and ΔFGH are similar, we need to analyze the angles given.
In ΔPRQ:
- ∠P = 30°
- ∠R = 127°
To find ∠Q, we can use the fact that the sum of the angles in a triangle is 180°:
∠Q = 180° - (∠P + ∠R)
∠Q = 180° - (30° + 127°) = 180° - 157° = 23°
In ΔFGH:
- ∠H = 30°
- ∠G = 23°
To find ∠F, we also use the same principle:
∠F = 180° - (∠H + ∠G)
∠F = 180° - (30° + 23°) = 180° - 53° = 127°
Now we have the angles:
- In ΔPRQ: ∠P = 30°, ∠R = 127°, ∠Q = 23°
- In ΔFGH: ∠H = 30°, ∠G = 23°, ∠F = 127°
Comparing the angles:
- ∠P = ∠H = 30°
- ∠R = ∠F = 127°
- ∠Q = ∠G = 23°
Since two triangles have two pairs of corresponding angles equal, they are similar by the AA (Angle-Angle) criterion.
Therefore, the correct answer is **AA**.
    
In ΔPRQ:
- ∠P = 30°
- ∠R = 127°
To find ∠Q, we can use the fact that the sum of the angles in a triangle is 180°:
∠Q = 180° - (∠P + ∠R)
∠Q = 180° - (30° + 127°) = 180° - 157° = 23°
In ΔFGH:
- ∠H = 30°
- ∠G = 23°
To find ∠F, we also use the same principle:
∠F = 180° - (∠H + ∠G)
∠F = 180° - (30° + 23°) = 180° - 53° = 127°
Now we have the angles:
- In ΔPRQ: ∠P = 30°, ∠R = 127°, ∠Q = 23°
- In ΔFGH: ∠H = 30°, ∠G = 23°, ∠F = 127°
Comparing the angles:
- ∠P = ∠H = 30°
- ∠R = ∠F = 127°
- ∠Q = ∠G = 23°
Since two triangles have two pairs of corresponding angles equal, they are similar by the AA (Angle-Angle) criterion.
Therefore, the correct answer is **AA**.
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