Add: (4d−3)+(12d+4)

Question

.(1 point)

Answer 1

To add the expressions $(4d-3)+(12d+4)$, follow these steps:

1. Combine like terms.
2. Combine the $d$ terms: $4d+12d=16d$.
3. Combine the constant terms: $-3+4=1$.

Putting it all together, we have:

$$(4d-3)+(12d+4)=16d+1$$

So, the final answer is $16d+1$.