Sure! I can help you with solving equations. Please provide the specific equation or equations you would like assistance with, and let me know if there are any particular methods or topics you would like to focus on (e.g., linear equations, quadratic equations, systems of equations, etc.).
Solving Equations Apply
9 answers
Sure! Here are a variety of equations for you to solve, ranging from linear to quadratic to systems of equations. Try solving them, and feel free to ask for help if needed!
Linear Equations
- \( 3x + 5 = 20 \)
- \( 2y - 4 = 10 \)
- \( 7 - 2z = 1 \)
Quadratic Equations
- \( x^2 - 5x + 6 = 0 \)
- \( 2x^2 + 3x - 5 = 0 \)
- \( x^2 + 4x + 4 = 0 \)
Systems of Equations
\[ \begin{align*} x + 2y &= 8 \ 3x - y &= 7 \ \end{align*} \] 8. \[ \begin{align*} 2a + 3b &= 12 \ 4a - b &= 1 \ \end{align*} \]
Inequalities
- \( 5x - 3 < 2 \)
- \( -2y + 6 \geq 10 \)
Give these a try, and let me know if you'd like any hints or solutions!
To solve the equation \( 3x + 5 = 20 \), follow these steps:
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Subtract 5 from both sides to isolate the term with \( x \): \[ 3x + 5 - 5 = 20 - 5 \] This simplifies to: \[ 3x = 15 \]
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Divide both sides by 3 to solve for \( x \): \[ x = \frac{15}{3} \] This simplifies to: \[ x = 5 \]
So, the solution to the equation \( 3x + 5 = 20 \) is \( x = 5 \).
To solve the equation \( x + 2y = 8 \) for \( x \) in terms of \( y \) (or vice versa), follow these steps:
Solving for \( x \)
- Isolate \( x \) on one side of the equation: \[ x = 8 - 2y \]
This represents \( x \) in terms of \( y \).
Solving for \( y \)
If you'd like to solve for \( y \) in terms of \( x \):
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Rearrange the original equation to isolate \( y \): \[ 2y = 8 - x \]
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Divide both sides by 2: \[ y = \frac{8 - x}{2} \]
Summary of Solutions
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In terms of \( y \): \[ x = 8 - 2y \]
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In terms of \( x \): \[ y = \frac{8 - x}{2} \]
If you are looking for specific values of \( x \) and \( y \), please provide another equation to create a system, and I can help you find the exact values!
To solve the equation \( 4a - 6 = 1 \), follow these steps:
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Add 6 to both sides to isolate the term with \( a \): \[ 4a - 6 + 6 = 1 + 6 \] This simplifies to: \[ 4a = 7 \]
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Divide both sides by 4 to solve for \( a \): \[ a = \frac{7}{4} \]
So, the solution to the equation \( 4a - 6 = 1 \) is: \[ a = \frac{7}{4} \quad \text{or} \quad a = 1.75 \]