Question

Two bowling balls of different masses collide while accelerating at 1.875 m/s
. The first ball,rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What forcedoes the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?
(1 point)
2
7.5 N to the left
8.875 N to the right
13.125 N to the right
3.73 N to the right

Answer 1

To determine the force exerted by the 7 kg bowling ball on the 4 kg bowling ball during their collision while they are both accelerating at \(1.875 \, \text{m/s}^2\), we can use Newton's second law of motion:

\[
F = ma
\]

Where:
- \( F \) is the force,
- \( m \) is the mass of the object,
- \( a \) is the acceleration.

Using this for the 7 kg ball, we get:

\[
F = (7 \, \text{kg})(1.875 \, \text{m/s}^2) = 13.125 \, \text{N}
\]

Since the 7 kg ball is rolling to the right and exerting this force on the 4 kg ball (which is rolling to the left), this force would be considered as acting to the right.

Therefore, the answer is:

**13.125 N to the right.**