Mrs. McDonald is going to buy coffee and tea for her local food pantry. At Costless she can buy a canister of coffee, c

Question

, for $7 and a box of tea, b
, for $4. This is modeled by 7c+4b
. Evaluate for c=10
and b=8
to find how much it will cost Mrs. McDonald to purchase 10 canisters of coffee and 8 boxes of tea.(1 point)
Responses

$592
$592

$96
$96

$29
$29

$102

Answer 1

To find the total cost for Mrs. McDonald to purchase 10 canisters of coffee and 8 boxes of tea, we can use the formula given, which is:

$$7c+4b$$

Where:

• $c$ is the number of canisters of coffee,
• $b$ is the number of boxes of tea.

Substituting $c=10$ and $b=8$ into the equation:

$$7(10)+4(8)$$

Calculating each term:

1. $7(10)=70$
2. $4(8)=32$

Now, add these two results together:

$$70+32=102$$

Therefore, the total cost for Mrs. McDonald to purchase 10 canisters of coffee and 8 boxes of tea is $102.

The correct response is:

$102

Answer 2

Simplify 79h + 10 − 49h − 3
.(1 point)
Responses

39h + 7 = 13h + 7
Start Fraction 3 over 9 End Fraction h plus 7 equals Start Fraction 1 over 3 End Fraction h plus 7

318h + 7 = 16h + 7
Start Fraction 3 over 18 End Fraction h plus 7 equals Start Fraction 1 over 6 End Fraction h plus 7

318h2 + 7 = 16h2 + 7
Start Fraction 3 over 18 End Fraction h squared plus 7 equals Start Fraction 1 over 6 End Fraction h squared plus 7

39h2 + 7 = 13h2 + 7

Answer 3

To simplify the expression $79h+10-49h-3$, we can follow these steps:

1. Combine the like terms involving $h$: $$79h-49h=30h$$

2. Combine the constant terms: $$10-3=7$$

Putting it all together, we get: $$30h+7$$

Now let's compare this result with the options provided:

1. $39h+7=13h+7$
2. $\frac{3}{9}h+7=\frac{1}{3}h+7$
3. $\frac{3}{18}{h}^2+7=\frac{1}{6}{h}^2+7$
4. $39h^2+7=13h^2+7$

None of these responses match the simplified expression $30h+7$. It appears there might have been an error in the options provided or in my calculations.

If the task was simply to simplify $79h+10-49h-3$, the correct simplified expression is:

$30h+7$.

Answer 4

Simplify 7/9h + 10 − 4/9h − 3
.(1 point)
Responses

3/9h + 7 = 1/3h + 7
Start Fraction 3 over 9 End Fraction h plus 7 equals Start Fraction 1 over 3 End Fraction h plus 7

318h + 7 = 16h + 7
Start Fraction 3 over 18 End Fraction h plus 7 equals Start Fraction 1 over 6 End Fraction h plus 7

318h2 + 7 = 16h2 + 7
Start Fraction 3 over 18 End Fraction h squared plus 7 equals Start Fraction 1 over 6 End Fraction h squared plus 7

39h2 + 7 = 13h2 + 7

Answer 5

To simplify the expression $\frac{7}{9}h+10-\frac{4}{9}h-3$, we will follow these steps:

1. Combine like terms (the terms with $h$): $$\frac{7}{9}h-\frac{4}{9}h=\frac{7-4}{9}h=\frac{3}{9}h$$

2. Combine the constant terms: $$10-3=7$$

Putting it all together, the expression simplifies to: $$\frac{3}{9}h+7$$

3. Further simplify $\frac{3}{9}h$: $$\frac{3}{9}h=\frac{1}{3}h$$

So we can rewrite the final expression as: $$\frac{1}{3}h+7$$

Now, comparing with the options provided:

1. $\frac{3}{9}h+7=\frac{1}{3}h+7$
2. $\frac{3}{18}h+7=\frac{1}{6}h+7$
3. $\frac{3}{18}{h}^2+7=\frac{1}{6}{h}^2+7$
4. $39h^2+7=13h^2+7$

The correct option that matches our simplified expression is:

$\frac{3}{9}h+7=\frac{1}{3}h+7$.

Answer 6

Simplify 38x−910y+38x+710y
.(1 point)
Responses

68x+210y=34x+15y
Start Fraction 6 over 8 End Fraction x plus Start Fraction 2 over 10 End Fraction y equals Start Fraction 3 over 4 End Fraction x plus Start Fraction 1 over 5 End Fraction y

68x−210y=34x−15y
Start Fraction 6 over 8 End Fraction x minus Start Fraction 2 over 10 End Fraction y equals Start Fraction 3 over 4 End Fraction x minus Start Fraction 1 over 5 End Fraction y

616x+220y=38x+110y
Start Fraction 6 over 16 End Fraction x plus Start Fraction 2 over 20 End Fraction y equals Start Fraction 3 over 8 End Fraction x plus Start Fraction 1 over 10 End Fraction y

616x−220y=38x−110y

Answer 7

Let's simplify the expression $38x-910y+38x+710y$.

1. Combine the like terms involving $x$: $$38x+38x=76x$$

2. Combine the like terms involving $y$: $$-910y+710y=-200y$$

Putting it all together, we have: $$76x-200y$$

Now, let's look through the provided options to see if any match our simplified expression:

1. $68x+210y=34x+15y$
2. $68x-210y=34x-15y$
3. $616x+220y=38x+110y$
4. $616x-220y=38x-110y$

None of these options match our simplified expression $76x-200y$.

Conclusion

The final simplified expression is: $$76x-200y$$

Please let me know if there are specific conditions or modifications you would like reflected in the simplification process!

Answer 8

Simplify 3/8x−9/10y+3/8x+7/10y
.(1 point)
Responses

6/8x+2/10y=3/4x+1/5y
Start Fraction 6 over 8 End Fraction x plus Start Fraction 2 over 10 End Fraction y equals Start Fraction 3 over 4 End Fraction x plus Start Fraction 1 over 5 End Fraction y

6/8x−2/10y=3/4x−1/5y
Start Fraction 6 over 8 End Fraction x minus Start Fraction 2 over 10 End Fraction y equals Start Fraction 3 over 4 End Fraction x minus Start Fraction 1 over 5 End Fraction y

6/16x+2/20y=3/8x+1/10y
Start Fraction 6 over 16 End Fraction x plus Start Fraction 2 over 20 End Fraction y equals Start Fraction 3 over 8 End Fraction x plus Start Fraction 1 over 10 End Fraction y

6/16x−2/20y=3/8x−1/10y

Answer 9

To simplify the expression $\frac{3}{8}x-\frac{9}{10}y+\frac{3}{8}x+\frac{7}{10}y$, we will follow these steps:

1. Combine the like terms involving $x$: $$\frac{3}{8}x+\frac{3}{8}x=\frac{6}{8}x$$

2. Combine the like terms involving $y$: $$-\frac{9}{10}y+\frac{7}{10}y=-\frac{2}{10}y$$

Putting it all together, we get: $$\frac{6}{8}x-\frac{2}{10}y$$

Next, we can simplify the coefficients further:

• $\frac{6}{8}x$ simplifies to $\frac{3}{4}x$ (dividing the numerator and the denominator by 2).
• $-\frac{2}{10}y$ simplifies to $-\frac{1}{5}y$ (dividing the numerator and the denominator by 2).

Thus, the simplified expression can also be written as: $$\frac{3}{4}x-\frac{1}{5}y$$

Now, let's compare this with the provided options:

1. $\frac{6}{8}x+\frac{2}{10}y=\frac{3}{4}x+\frac{1}{5}y$
2. $\frac{6}{8}x-\frac{2}{10}y=\frac{3}{4}x-\frac{1}{5}y$
3. $\frac{6}{16}x+\frac{2}{20}y=\frac{3}{8}x+\frac{1}{10}y$
4. $\frac{6}{16}x-\frac{2}{20}y=\frac{3}{8}x-\frac{1}{10}y$

From the simplified expression $\frac{6}{8}x-\frac{2}{10}y$, we can directly see that this matches option 2:

$\frac{6}{8}x-\frac{2}{10}y=\frac{3}{4}x-\frac{1}{5}y$.