Mrs. McDonald is going to buy coffee and tea for her local food pantry. At Costless she can buy a canister of coffee, c

To find the total cost for Mrs. McDonald to purchase 10 canisters of coffee and 8 boxes of tea, we can use the formula given, which is:

\[ 7c + 4b \]

Where:

• \( c \) is the number of canisters of coffee,
• \( b \) is the number of boxes of tea.

Substituting \( c = 10 \) and \( b = 8 \) into the equation:

\[ 7(10) + 4(8) \]

Calculating each term:

1. \( 7(10) = 70 \)
2. \( 4(8) = 32 \)

Now, add these two results together:

\[ 70 + 32 = 102 \]

Therefore, the total cost for Mrs. McDonald to purchase 10 canisters of coffee and 8 boxes of tea is $102.

The correct response is:

$102

Simplify 79h + 10 − 49h − 3
.(1 point)
Responses

39h + 7 = 13h + 7
Start Fraction 3 over 9 End Fraction h plus 7 equals Start Fraction 1 over 3 End Fraction h plus 7

318h + 7 = 16h + 7
Start Fraction 3 over 18 End Fraction h plus 7 equals Start Fraction 1 over 6 End Fraction h plus 7

318h2 + 7 = 16h2 + 7
Start Fraction 3 over 18 End Fraction h squared plus 7 equals Start Fraction 1 over 6 End Fraction h squared plus 7

39h2 + 7 = 13h2 + 7

To simplify the expression \( 79h + 10 - 49h - 3 \), we can follow these steps:

1. Combine the like terms involving \( h \): \[ 79h - 49h = 30h \]

2. Combine the constant terms: \[ 10 - 3 = 7 \]

Putting it all together, we get: \[ 30h + 7 \]

Now let's compare this result with the options provided:

1. \( 39h + 7 = 13h + 7 \)
2. \( \frac{3}{9}h + 7 = \frac{1}{3}h + 7 \)
3. \( \frac{3}{18}h^2 + 7 = \frac{1}{6}h^2 + 7 \)
4. \( 39h^2 + 7 = 13h^2 + 7 \)

None of these responses match the simplified expression \( 30h + 7 \). It appears there might have been an error in the options provided or in my calculations.

If the task was simply to simplify \( 79h + 10 - 49h - 3 \), the correct simplified expression is:

\( 30h + 7 \).

Simplify 7/9h + 10 − 4/9h − 3
.(1 point)
Responses

3/9h + 7 = 1/3h + 7
Start Fraction 3 over 9 End Fraction h plus 7 equals Start Fraction 1 over 3 End Fraction h plus 7

318h + 7 = 16h + 7
Start Fraction 3 over 18 End Fraction h plus 7 equals Start Fraction 1 over 6 End Fraction h plus 7

318h2 + 7 = 16h2 + 7
Start Fraction 3 over 18 End Fraction h squared plus 7 equals Start Fraction 1 over 6 End Fraction h squared plus 7

39h2 + 7 = 13h2 + 7

To simplify the expression \( \frac{7}{9}h + 10 - \frac{4}{9}h - 3 \), we will follow these steps:

1. Combine like terms (the terms with \( h \)): \[ \frac{7}{9}h - \frac{4}{9}h = \frac{7 - 4}{9}h = \frac{3}{9}h \]

2. Combine the constant terms: \[ 10 - 3 = 7 \]

Putting it all together, the expression simplifies to: \[ \frac{3}{9}h + 7 \]

3. Further simplify \(\frac{3}{9}h\): \[ \frac{3}{9}h = \frac{1}{3}h \]

So we can rewrite the final expression as: \[ \frac{1}{3}h + 7 \]

Now, comparing with the options provided:

1. \( \frac{3}{9}h + 7 = \frac{1}{3}h + 7 \)
2. \( \frac{3}{18}h + 7 = \frac{1}{6}h + 7 \)
3. \( \frac{3}{18}h^2 + 7 = \frac{1}{6}h^2 + 7 \)
4. \( 39h^2 + 7 = 13h^2 + 7 \)

The correct option that matches our simplified expression is:

\( \frac{3}{9}h + 7 = \frac{1}{3}h + 7 \).

Simplify 38x−910y+38x+710y
.(1 point)
Responses

68x+210y=34x+15y
Start Fraction 6 over 8 End Fraction x plus Start Fraction 2 over 10 End Fraction y equals Start Fraction 3 over 4 End Fraction x plus Start Fraction 1 over 5 End Fraction y

68x−210y=34x−15y
Start Fraction 6 over 8 End Fraction x minus Start Fraction 2 over 10 End Fraction y equals Start Fraction 3 over 4 End Fraction x minus Start Fraction 1 over 5 End Fraction y

616x+220y=38x+110y
Start Fraction 6 over 16 End Fraction x plus Start Fraction 2 over 20 End Fraction y equals Start Fraction 3 over 8 End Fraction x plus Start Fraction 1 over 10 End Fraction y

616x−220y=38x−110y

Let's simplify the expression \( 38x - 910y + 38x + 710y \).

1. Combine the like terms involving \( x \): \[ 38x + 38x = 76x \]

2. Combine the like terms involving \( y \): \[ -910y + 710y = -200y \]

Putting it all together, we have: \[ 76x - 200y \]

Now, let's look through the provided options to see if any match our simplified expression:

1. \( 68x + 210y = 34x + 15y \)
2. \( 68x - 210y = 34x - 15y \)
3. \( 616x + 220y = 38x + 110y \)
4. \( 616x - 220y = 38x - 110y \)

None of these options match our simplified expression \( 76x - 200y \).

Conclusion

The final simplified expression is: \[ 76x - 200y \]

Please let me know if there are specific conditions or modifications you would like reflected in the simplification process!

Simplify 3/8x−9/10y+3/8x+7/10y
.(1 point)
Responses

6/8x+2/10y=3/4x+1/5y
Start Fraction 6 over 8 End Fraction x plus Start Fraction 2 over 10 End Fraction y equals Start Fraction 3 over 4 End Fraction x plus Start Fraction 1 over 5 End Fraction y

6/8x−2/10y=3/4x−1/5y
Start Fraction 6 over 8 End Fraction x minus Start Fraction 2 over 10 End Fraction y equals Start Fraction 3 over 4 End Fraction x minus Start Fraction 1 over 5 End Fraction y

6/16x+2/20y=3/8x+1/10y
Start Fraction 6 over 16 End Fraction x plus Start Fraction 2 over 20 End Fraction y equals Start Fraction 3 over 8 End Fraction x plus Start Fraction 1 over 10 End Fraction y

6/16x−2/20y=3/8x−1/10y

To simplify the expression \( \frac{3}{8}x - \frac{9}{10}y + \frac{3}{8}x + \frac{7}{10}y \), we will follow these steps:

1. Combine the like terms involving \( x \): \[ \frac{3}{8}x + \frac{3}{8}x = \frac{6}{8}x \]

2. Combine the like terms involving \( y \): \[ -\frac{9}{10}y + \frac{7}{10}y = -\frac{2}{10}y \]

Putting it all together, we get: \[ \frac{6}{8}x - \frac{2}{10}y \]

Next, we can simplify the coefficients further:

• \( \frac{6}{8}x \) simplifies to \( \frac{3}{4}x \) (dividing the numerator and the denominator by 2).
• \( -\frac{2}{10}y \) simplifies to \( -\frac{1}{5}y \) (dividing the numerator and the denominator by 2).

Thus, the simplified expression can also be written as: \[ \frac{3}{4}x - \frac{1}{5}y \]

Now, let's compare this with the provided options:

1. \(\frac{6}{8}x + \frac{2}{10}y = \frac{3}{4}x + \frac{1}{5}y\)
2. \(\frac{6}{8}x - \frac{2}{10}y = \frac{3}{4}x - \frac{1}{5}y\)
3. \(\frac{6}{16}x + \frac{2}{20}y = \frac{3}{8}x + \frac{1}{10}y\)
4. \(\frac{6}{16}x - \frac{2}{20}y = \frac{3}{8}x - \frac{1}{10}y\)

From the simplified expression \( \frac{6}{8}x - \frac{2}{10}y \), we can directly see that this matches option 2:

\(\frac{6}{8}x - \frac{2}{10}y = \frac{3}{4}x - \frac{1}{5}y\).