Question

find the volume of cone with the radius 4 and hight 12

Answer 1

find the volume of a cilinder with radius 5 hight 15

Answer 2

sorry its a cone

Answer 3

find the volume of a sphere with a radius of 5

Answer 4

find valume of sphere with radius 4

Answer 5

The volume \( V \) of a cone can be calculated using the formula:

\[
V = \frac{1}{3} \pi r^2 h
\]

where:
- \( r \) is the radius of the base of the cone,
- \( h \) is the height of the cone.

Given:
- Radius \( r = 4 \)
- Height \( h = 12 \)

Substituting the values into the formula:

\[
V = \frac{1}{3} \pi (4)^2 (12)
\]

Calculating \( (4)^2 \):

\[
(4)^2 = 16
\]

Now substituting back:

\[
V = \frac{1}{3} \pi (16)(12)
\]

Calculating \( 16 \times 12 \):

\[
16 \times 12 = 192
\]

Now substituting this value in:

\[
V = \frac{1}{3} \pi (192)
\]

Calculating \( \frac{192}{3} \):

\[
\frac{192}{3} = 64
\]

Thus, the volume \( V \) simplifies to:

\[
V = 64\pi
\]

Therefore, the volume of the cone is

\[
\boxed{64\pi}
\]

If you want a numerical approximation, you can use \( \pi \approx 3.14 \):

\[
V \approx 64 \times 3.14 \approx 200.96
\]

So the volume is approximately \( 200.96 \) cubic units.

Answer 6

The volume \( V \) of a cylinder can be calculated using the formula:

\[
V = \pi r^2 h
\]

where:
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.

Given:
- Radius \( r = 5 \)
- Height \( h = 15 \)

Substituting the values into the formula:

\[
V = \pi (5)^2 (15)
\]

Calculating \( (5)^2 \):

\[
(5)^2 = 25
\]

Now substituting this value in:

\[
V = \pi (25)(15)
\]

Calculating \( 25 \times 15 \):

\[
25 \times 15 = 375
\]

Thus, the volume \( V \) simplifies to:

\[
V = 375\pi
\]

Therefore, the volume of the cylinder is

\[
\boxed{375\pi}
\]

If you want a numerical approximation, you can use \( \pi \approx 3.14 \):

\[
V \approx 375 \times 3.14 \approx 1177.5
\]

So the volume is approximately \( 1177.5 \) cubic units.

Answer 7

No problem! Let's calculate the volume of a cone with a radius of 5 and a height of 15.

The volume \( V \) of a cone can be calculated using the formula:

\[
V = \frac{1}{3} \pi r^2 h
\]

where:
- \( r \) is the radius of the base of the cone,
- \( h \) is the height of the cone.

Given:
- Radius \( r = 5 \)
- Height \( h = 15 \)

Substituting the values into the formula:

\[
V = \frac{1}{3} \pi (5)^2 (15)
\]

Calculating \( (5)^2 \):

\[
(5)^2 = 25
\]

Now substituting this value back into the formula:

\[
V = \frac{1}{3} \pi (25)(15)
\]

Next, calculate \( 25 \times 15 \):

\[
25 \times 15 = 375
\]

Now substituting this value in:

\[
V = \frac{1}{3} \pi (375)
\]

Calculating \( \frac{375}{3} \):

\[
\frac{375}{3} = 125
\]

Thus, the volume \( V \) simplifies to:

\[
V = 125\pi
\]

Therefore, the volume of the cone is

\[
\boxed{125\pi}
\]

If you want a numerical approximation, using \( \pi \approx 3.14 \):

\[
V \approx 125 \times 3.14 \approx 392.5
\]

So the volume is approximately \( 392.5 \) cubic units.

Answer 8

The volume \( V \) of a sphere can be calculated using the formula:

\[
V = \frac{4}{3} \pi r^3
\]

where:
- \( r \) is the radius of the sphere.

Given:
- Radius \( r = 5 \)

Substituting the value into the formula:

\[
V = \frac{4}{3} \pi (5)^3
\]

Calculating \( (5)^3 \):

\[
(5)^3 = 125
\]

Now substituting this value back into the formula:

\[
V = \frac{4}{3} \pi (125)
\]

Calculating \( \frac{4 \times 125}{3} \):

\[
V = \frac{500}{3} \pi
\]

Thus, the volume \( V \) simplifies to:

\[
V = \frac{500}{3} \pi
\]

Therefore, the volume of the sphere is

\[
\boxed{\frac{500}{3} \pi}
\]

If you'd like a numerical approximation, using \( \pi \approx 3.14 \):

\[
V \approx \frac{500}{3} \times 3.14 \approx 523.33
\]

So the volume is approximately \( 523.33 \) cubic units.

Answer 9

To find the volume \( V \) of a sphere, you can use the formula:

\[
V = \frac{4}{3} \pi r^3
\]

where:
- \( r \) is the radius of the sphere.

Given:
- Radius \( r = 4 \)

Substituting the value into the formula:

\[
V = \frac{4}{3} \pi (4)^3
\]

Calculating \( (4)^3 \):

\[
(4)^3 = 64
\]

Now substituting this value back into the formula:

\[
V = \frac{4}{3} \pi (64)
\]

Calculating \( \frac{4 \times 64}{3} \):

\[
V = \frac{256}{3} \pi
\]

Thus, the volume \( V \) simplifies to:

\[
V = \frac{256}{3} \pi
\]

Therefore, the volume of the sphere is

\[
\boxed{\frac{256}{3} \pi}
\]

If you would like a numerical approximation using \( \pi \approx 3.14 \):

\[
V \approx \frac{256}{3} \times 3.14 \approx 268.67
\]

So the volume is approximately \( 268.67 \) cubic units.