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-6 + 3•5

V16 + 32 ÷ 8.
Which operator can be inserted to make the statement true?

1 answer

To solve the expressions step-by-step:

  1. For the first expression: \(-6 + 3 \times 5\)

    Calculate \(3 \times 5\): \[ = 15 \]

    Now, calculate \(-6 + 15\): \[ -6 + 15 = 9 \]

  2. For the second expression: \(\sqrt{16} + 32 \div 8\)

    Calculate \(\sqrt{16}\): \[ = 4 \]

    Now, calculate \(32 \div 8\): \[ = 4 \]

    Now add the results: \[ 4 + 4 = 8 \]

Now we have:

  • The first expression evaluates to \(9\).
  • The second expression evaluates to \(8\).

Thus, the statement is \(9\) and \(8\). To find an operator that can be inserted to make a true statement, consider common mathematical operations like either using an equals sign or an inequality.

  1. If we insert an equality operator \(=\): \[ 9 = 8 \quad \text{(not true)} \]

  2. If we insert a greater than operator \(>\): \[ 9 > 8 \quad \text{(true)} \]

In conclusion, the operator that can be used to relate the two statements and make a true statement is \(>\).