Question

-6 + 3•5
V16 + 32 ÷ 8.
Which operator can be inserted to make the statement true?

Answer 1

To solve the expressions step-by-step:

1. For the first expression:
\(-6 + 3 \times 5\)

Calculate \(3 \times 5\):
\[
= 15
\]

Now, calculate \(-6 + 15\):
\[
-6 + 15 = 9
\]

2. For the second expression:
\(\sqrt{16} + 32 \div 8\)

Calculate \(\sqrt{16}\):
\[
= 4
\]

Now, calculate \(32 \div 8\):
\[
= 4
\]

Now add the results:
\[
4 + 4 = 8
\]

Now we have:
- The first expression evaluates to \(9\).
- The second expression evaluates to \(8\).

Thus, the statement is \(9\) and \(8\). To find an operator that can be inserted to make a true statement, consider common mathematical operations like either using an equals sign or an inequality.

1. If we insert an equality operator \(=\):
\[
9 = 8 \quad \text{(not true)}
\]

2. If we insert a greater than operator \(>\):
\[
9 > 8 \quad \text{(true)}
\]

In conclusion, the operator that can be used to relate the two statements and make a true statement is \(>\).