A) Right triangle ABC has side lengths AB = 6, BC = 8, and CA = 10. A second right triangle has corresponding vertices of A', B', and C", with side lengths of 32, 40, and 24. In 3-5 sentences, describe how to find the ratio of the side opposite A to the hypotenuse of triangle ABC. Then use this ratio to identify the location of point A' in the second right triangle.. (1 point) The ratio of the opposite side to the hypotenuse is length 40. and point is opposite the side that has The ratio of the opposite side to the hypotenuse is, and point is opposite the side that has 5 length 32. The ratio of the opposite side to the hypotenuse is, and point is opposite the side that has length 24

To find the ratio of the side opposite angle A to the hypotenuse in triangle ABC, we identify the side lengths: AB = 6 (opposite angle A), AC = 10 (hypotenuse). The ratio is calculated as the length of the opposite side divided by the length of the hypotenuse, which gives us 6/10 or simplified to 3/5.

In the second triangle with corresponding sides of 32 (opposite angle A'), 40 (hypotenuse), and 24 (the other side), we can use this ratio to locate point A'. Since the ratio 3/5 must hold, and the hypotenuse is 40, we find the side opposite A' as (3/5) * 40 = 24. Therefore, point A' is located opposite the side with length 24 in the second right triangle, which corresponds to the side opposite angle A.