What is the x-intercept of the line with this equation −2x+12y=18?

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, 0)

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To find the x-intercept of the line given by the equation \(-2x + 12y = 18\), you need to set \(y = 0\) and solve for \(x\).

Substituting \(y = 0\) into the equation:

\[ -2x + 12(0) = 18 \]

This simplifies to:

\[ -2x = 18 \]

Now, solve for \(x\) by dividing both sides by \(-2\):

\[ x = \frac{18}{-2} = -9 \]

Therefore, the x-intercept is \((-9, 0)\).

So, the answer is:

\[ (-9, 0) \]

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