In mice, the gene for tail length has two alleles. A long tail is dominant to a short tail. If a long-tailed mouse that is heterozygous mates with a short-tailed mouse, what are the chances of having offspring with short tails?(1 point) Responses 25% 25% 75% 75% 50% 50% 100%

To solve this problem, we can set up a Punnett square to determine the possible genotypes of the offspring.

Let's denote the alleles as follows:

• L = allele for long tail (dominant)
• l = allele for short tail (recessive)

The genotypes of the mice are:

• The long-tailed mouse that is heterozygous would have the genotype Ll.
• The short-tailed mouse has the genotype ll.

Now, let's set up a Punnett square:

       L       l
     ----------------
  l |   Ll    |   ll   |
  l |   Ll    |   ll   |

The possible genotypes of the offspring are:

• Ll (long tail) = 2 instances
• ll (short tail) = 2 instances

From the Punnett square, we see that:

• 2 out of 4 (50%) of the offspring will have a long tail (Ll).
• 2 out of 4 (50%) of the offspring will have a short tail (ll).

Therefore, the chances of having offspring with short tails is 50%.