To solve the equation \( \frac{1}{3}(6x - 9) = -33 \), follow these steps:
Step 1: Eliminate the fraction by multiplying both sides by 3. \[ 3 \times \frac{1}{3}(6x - 9) = 3 \times -33 \] This simplifies to: \[ 6x - 9 = -99 \]
Step 2: Add 9 to both sides to isolate the term with \( x \). \[ 6x - 9 + 9 = -99 + 9 \] This simplifies to: \[ 6x = -90 \]
Step 3: Divide both sides by 6 to solve for \( x \). \[ x = \frac{-90}{6} \] This simplifies to: \[ x = -15 \]
So, the corrected order of the steps is:
- Step 1: Eliminate the fraction by multiplying both sides by 3.
- Step 2: Add 9 to both sides.
- Step 3: Divide both sides by 6.
For the second part of the question, the solution for \( x \) is: \[ \boxed{x = -15} \]