What is a point-slope equation of the line with slope -13 that goes through the point (5, 7)?

31-7 = -13(x- 5)
4+ 5=-13(x +7)
01-5--130-71

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
4 hours ago

To create the point-slope equation of a line given a slope and a point, you can use the point-slope form of the equation:

\[ y - y_1 = m(x - x_1) \]

where \(m\) is the slope, and \((x_1, y_1)\) is the point through which the line passes.

In this case, the slope \(m = -13\) and the point is \((5, 7)\), so \(x_1 = 5\) and \(y_1 = 7\).

Plugging these values into the equation:

\[ y - 7 = -13(x - 5) \]

So the point-slope equation of the line is:

\[ y - 7 = -13(x - 5) \]

You can simplify this further if needed, but this is the point-slope form of the line.