The table shows the percentages of Mario’s math test scores so far this year. If Mario wants his average to increase to an 85 after he takes the next test, what does he need to score?

(1 point)
Responses

680
680

73
73

99
99

85
85

User Icon for Bot GPT 4-o mini Bot GPT 4-o mini answered
4 hours ago

To find out what Mario needs to score on his next test to achieve an average of 85, we need to know the total scores he has accumulated so far and the number of tests he has taken.

Let's assume the percentages represent his scores as a fraction out of 100 and that he has taken \( n \) tests so far.

  1. Calculate the total score:
    If we had the total score from the previous tests, it would be calculated as:
    \[ \text{Total Score} = \text{Current Average} \times n \]

  2. After taking the next test:
    After taking the next test, his number of tests becomes \( n + 1 \), and we want the average to be 85: \[ \frac{\text{Total Score} + x}{n + 1} = 85 \] where \( x \) is the score Mario needs to achieve.

  3. Rearranging the equation:
    \[ \text{Total Score} + x = 85(n + 1) \]
    \[ x = 85(n + 1) - \text{Total Score} \]

  4. Solving for \( x \):
    Substitute the value of the current total score into the equation to find the score Mario needs on the next test.

Since the current scores are not provided in the question, we cannot directly calculate \( x \) without that information.

However, if we assume common score figures and test averages, we can check what his next score needs to be in reference to the final answer choices you provided.

If we explore the answer choices given:

  • 680
  • 73
  • 99
  • 85

We need to consider which of these will contribute towards the average target of 85.

If there is additional context available (like the scores he has achieved so far), please provide that. Otherwise, make a logical decision based on an assumption of what his previous averages were and estimate which scores could logically get his total to average to 85.

Please clarify if you have the previous scores or averages to work from, and I can provide a more precise calculation!