Question
can you buy 34 book if each coswt 50 cents and you only had twenty dollars?
Answers
Answer
say we had soft cover books costing 50 cents and board books costing 1.50 could i somehow get 34 books and use up all twenty bucks?
Answered by
GPT-4o mini
To determine if you can buy 34 books that each cost 50 cents with $20, we first need to calculate the total cost of the books.
Each book costs $0.50, and if you want to buy 34 books, the total cost would be:
\[
34 \text{ books} \times 0.50 \text{ dollars/book} = 17 \text{ dollars}
\]
Now, you have $20. Since $20 is greater than $17, yes, you can buy 34 books for $17 and still have some money left over. Specifically, after the purchase, you would have:
\[
20 \text{ dollars} - 17 \text{ dollars} = 3 \text{ dollars}
\]
So, you can buy the 34 books and have $3 remaining.
Each book costs $0.50, and if you want to buy 34 books, the total cost would be:
\[
34 \text{ books} \times 0.50 \text{ dollars/book} = 17 \text{ dollars}
\]
Now, you have $20. Since $20 is greater than $17, yes, you can buy 34 books for $17 and still have some money left over. Specifically, after the purchase, you would have:
\[
20 \text{ dollars} - 17 \text{ dollars} = 3 \text{ dollars}
\]
So, you can buy the 34 books and have $3 remaining.
Answered by
GPT-4o mini
To find out if you can buy 34 books using exactly $20, with softcover books costing $0.50 and board books costing $1.50, we can set up the problem with some variables.
Let:
- \( s \) be the number of softcover books.
- \( b \) be the number of board books.
From the information given, you have the following two equations:
1. The total number of books:
\[
s + b = 34
\]
2. The total cost of the books:
\[
0.50s + 1.50b = 20
\]
Now we can solve these equations. To simplify the cost equation, let's multiply everything by 2 to eliminate the decimals:
\[
s + 3b = 40
\]
Now we have two equations to work with:
1. \( s + b = 34 \)
2. \( s + 3b = 40 \)
Next, we can subtract the first equation from the second:
\[
(s + 3b) - (s + b) = 40 - 34
\]
\[
2b = 6
\]
\[
b = 3
\]
Now that we know \( b = 3 \), we can substitute this value back into the first equation to find \( s \):
\[
s + 3 = 34
\]
\[
s = 34 - 3 = 31
\]
So, you can buy 31 softcover books and 3 board books. Let's check the total cost to ensure it equals $20:
- Cost of 31 softcover books: \( 31 \times 0.50 = 15.50 \)
- Cost of 3 board books: \( 3 \times 1.50 = 4.50 \)
- Total cost: \( 15.50 + 4.50 = 20 \)
Thus, yes, you can buy 34 books using up exactly $20, by purchasing 31 softcover books and 3 board books.
Let:
- \( s \) be the number of softcover books.
- \( b \) be the number of board books.
From the information given, you have the following two equations:
1. The total number of books:
\[
s + b = 34
\]
2. The total cost of the books:
\[
0.50s + 1.50b = 20
\]
Now we can solve these equations. To simplify the cost equation, let's multiply everything by 2 to eliminate the decimals:
\[
s + 3b = 40
\]
Now we have two equations to work with:
1. \( s + b = 34 \)
2. \( s + 3b = 40 \)
Next, we can subtract the first equation from the second:
\[
(s + 3b) - (s + b) = 40 - 34
\]
\[
2b = 6
\]
\[
b = 3
\]
Now that we know \( b = 3 \), we can substitute this value back into the first equation to find \( s \):
\[
s + 3 = 34
\]
\[
s = 34 - 3 = 31
\]
So, you can buy 31 softcover books and 3 board books. Let's check the total cost to ensure it equals $20:
- Cost of 31 softcover books: \( 31 \times 0.50 = 15.50 \)
- Cost of 3 board books: \( 3 \times 1.50 = 4.50 \)
- Total cost: \( 15.50 + 4.50 = 20 \)
Thus, yes, you can buy 34 books using up exactly $20, by purchasing 31 softcover books and 3 board books.
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